SQL将多个查询汇总为一个

Question

我有一个关于总结SQL查询的问题：

SELECT COUNT(fquantity) from items where fcategory="Crab"
SELECT COUNT(fquantity) from items where fcategory="Chicken"
SELECT COUNT(fquantity) from items where fcategory="Beancurd"
SELECT COUNT(fquantity) from items where fcategory="Pork"
SELECT COUNT(fquantity) from items where fcategory="Fish"
SELECT COUNT(fquantity) from items where fcategory="Premium"
SELECT COUNT(fquantity) from items where fcategory="Vegetable"
SELECT COUNT(fquantity) from items where fcategory="Prawn"

有没有办法将它们汇总到单个SQL查询中，该查询将返回包含2列数据（fcategory，count）的8行结果？

Answer 1

SELECT fcategory,count(fquantity) AS qty FROM items GROUP BY fcategory

Answer 2

使用group by按类别按类别对数据进行分组：

<强>查询

Select count(fquantity),
fcategory 
from items
group by fcategory