Question

我有两个名为clientorder和orderitemstatus的表。

OrderItem的

+-----+------------+-------------+
| clid| orderitem  | orderstatus |
+-----+------------+-------------+
| 1   | books      |   6         |
| 2   | books1     |   7         |
| 1   | books2     |   8         |
| 4   | books3     |   6         |
| 1   | books4     |   8         |
| 6   | books5     |   7         |
| 2   | books6     |   6         |
+-----+------------+-------------+

orderitemstatus

+----+---------------+
| id | iddescription |
+----+---------------+
| 6  | job held      |
| 7  | pre-press     |
| 8  | onqueue       |
| 9  | sent          |
+----+---------------+

现在我想计算客户端orderstatus的客户端ID，结果应该是

预期输出

+------+---------+-----------+---------+------+
| clid | jobheld | pre-press | onqueue | sent |
+------+---------+-----------+---------+------+
| 1    | 2       | 1         | 0       | 2    | 
| 2    | 2       | 1         | 0       | 2    |
| 3    | 4       | 1         | 0       | 2    |
| 6    | 1       | 1         | 0       | 2    |
+------+---------+-----------+---------+------+

我试过这个，但我只得到一份工作状态

查询

select count(cloi_current_status) as jobheld 
from dbo.CLOI_ClientOrderItems 
where cloi_current_status=9 and cl_id='1'

Answer 1

您需要使用PIVOT operator：

SELECT clid, [6] AS jobheld, [7] AS [pre-press], [8] AS onqueue, [9] AS [sent]
FROM clientorder
PIVOT
(
    COUNT(orderitem)
    FOR orderstatus IN ([6], [7], [8], [9])
) AS pvt

以下是我的数据结果：

+------+---------+-----------+---------+------+
| clid | jobheld | pre-press | onqueue | sent |
+------+---------+-----------+---------+------+
| 1    | 1       | 0         | 2       | 0    |
| 2    | 1       | 1         | 0       | 0    |
| 4    | 1       | 0         | 0       | 0    |
| 6    | 0       | 1         | 0       | 0    |
+------+---------+-----------+---------+------+

Answer 2

也许这会有所帮助：

SELECT i.clid,
       SUM(CASE WHEN s.iddescription = 'jobheld' THEN 1 ELSE 0 END) as jobheld,
       SUM(CASE WHEN s.iddescription = 'prep-press' THEN 1 ELSE 0 END) as pre_press,
       SUM(CASE WHEN s.iddescription = 'onqueue' THEN 1 ELSE 0 END) as onqueue,
       SUM(CASE WHEN s.iddescription = 'sent' THEN 1 ELSE 0 END) as sent,
       COUNT(*) AS total,
       SUM(CASE WHEN s.iddescription IN ('jobheld', 'pre-press', 'onqueue') THEN 1 ELSE 0 END) as whatever
  FROM orderitem i
  JOIN orderstatus s
    ON i.orderstatus = s.id
 GROUP
   BY i.clid

如何用sql中的两个不同表计数记录？

2 个答案: