所以我最近开始编写python，这个代码有一个问题。如果玩家在使用完毕后得到的答案不正确，那么它应该打印出它所做的答案，但只有在第一次播放时我才会再次播放，如果错误则不会告诉他们正确的答案。当玩家得到正确答案时，它也会这样做。当您再次使用播放功能时，计算机选择的数字保持不变。请尽量帮助我，但请记住，我的理解手段在python的某些方面非常有限。我已经收录了很多评论，以帮助其他人了解最新情况。我已经包含了我的代码以及我在shell中获得的内容。
代码：
#imports required modules
import random
from time import sleep
#correct number variable created
num = 0
#generates number at random
comp_num = random.randint(1,10)
print('I\'m thinking of a number guess what it is...\n')
#main game code
def main():
#lives created
lives = 3
#correct number variable reset
num = 0
while lives >= 1:
#player guesses
guess = int(input('Guess: '))
if comp_num == guess:
#if correct says well done
input('\nWell Done! You guessed Correctly!\n')
#player doesn't get told what the number is if there right
num = num +1
break
elif comp_num >= guess:
#if guess is too low tells player
#one live taken for incorrect guess
lives = lives -1
print('\nToo low!\n')
#player is told how many lives they have left
print('You guessed incorrectly. You have',lives,'live(s) remaining.\n')
elif comp_num <= guess:
#if guess is too high tells player
#one live taken for incorrect guess
lives = lives -1
print('\nToo high!\n')
#player is told how many lives they have left
print('You guessed incorrectly. You have',lives,'live(s) remaining.\n')
def end():
#asks player if they want to play again
play_again = input('Would you like to play again?[Y/N] ')
while play_again.lower() == 'y':
#if they do game resets and plays again
if play_again.lower() == 'y':
comp_num = random.randint(1,10)
print('\nI\'m thinking of a number guess what it is...\n')
main()
play_again = input('Would you like to play again?[Y/N] ')
if play_again.lower() == 'n':
break
if play_again.lower() == 'n':
#if they don't game ends
input('\nOk, Press enter to exit')
exit()
main()
if num != 1:
#if player guesses incorrectly they get told the correct awnser
print('The number I was thinking of was...',comp_num,'!\n')
end()
SHELL：
I'm thinking of a number guess what it is...
Guess: 5
Well Done! You guessed Correctly!
The number I was thinking of was... 5 !
Would you like to play again?[Y/N] y
I'm thinking of a number guess what it is...
Guess: 5
Well Done! You guessed Correctly!
Would you like to play again?[Y/N] y
I'm thinking of a number guess what it is...
Guess: 5
Well Done! You guessed Correctly!
Would you like to play again?[Y/N] y
I'm thinking of a number guess what it is...
Guess: 5
Well Done! You guessed Correctly!
答案 0 :(得分：0)
您的函数存在的问题是您有一个名为num的全局变量，但您的main函数还有一个名为num的局部变量。 num += 1内的main行只会更改局部变量。但是最后的if num != 1检查全局变量。
要解决此问题，请添加全局声明：
def main():
global num
# the rest of your code
为什么这样做？
在Python中，每次在函数中编写赋值语句（如num = 0或num += 1）时，都会创建一个局部变量 - 除非你明确告诉它不要，用{ {1}}声明。*因此，添加global表示现在没有局部变量global num，因此num会影响全局变量。
Defining Functions上的教程部分对此进行了更详细的说明。
*或num += 1声明，但您还不想了解。
然而，有一种更好的方法来解决这个问题。您可以nonlocal局部变量中的值，而不是使用全局变量。像这样：
return答案 1 :(得分：0)
好的，所以我的朋友看了我的代码，我们一起解决了。我们已经修复了保持不变的数字并通过这样做被告知正确的答案。
#imports required modules
import random
#correct number variable created
num = 0
#generates number at random
comp_num = random.randint(1,10)
print('I\'m thinking of a number guess what it is...\n')
#main game code
def main():
#generates number at random
comp_num = random.randint(1,10)
#set num as a global variable
global num
#lives created
lives = 3
while lives >= 1:
#player guesses
guess = int(input('Guess: '))
if comp_num == guess:
#if correct says well done
print('\nWell Done! You guessed Correctly!\n')
break
elif comp_num >= guess:
#if guess is too low tells player
#one live taken for incorrect guess
lives = lives -1
print('\nToo low!\n')
#player is told how many lives they have left
print('You guessed incorrectly. You have',lives,'live(s) remaining.\n')
if lives == 0:
#if player guesses incorrectly they get told the correct awnser
print('The number I was thinking of was...',comp_num,'!\n')
elif comp_num <= guess:
#if guess is too high tells player
#one live taken for incorrect guess
lives = lives -1
print('\nToo high!\n')
#player is told how many lives they have left
print('You guessed incorrectly. You have',lives,'live(s) remaining.\n')
if lives == 0:
#if player guesses incorrectly they get told the correct awnser
print('The number I was thinking of was...',comp_num,'!\n')
def end():
#asks player if they want to play again
play_again = input('Would you like to play again?[Y/N] ')
while play_again.lower() == 'y':
#if they do game resets and plays again
if play_again.lower() == 'y':
comp_num = random.randint(1,10)
print('\nI\'m thinking of a number guess what it is...\n')
main()
play_again = input('Would you like to play again?[Y/N] ')
if play_again.lower() == 'n':
break
if play_again.lower() == 'n':
#if they don't game ends
input('Ok, Press enter to exit')
exit()
#calls main section of game
main()
#calls end of game to give option of playing again and reseting game
end()
我要感谢所有帮助过的人，但我仍然无法在代码中看到问题，更不用说修复它了。出于这个原因，我将@abarnert的回答标记为接受的答案，因为他发现了这个错误。
答案 2 :(得分：-1)
您可以尝试使用此代码。我是作为学校作业做的
import random
print "Welcome to guess my number!"
number = random.randint(1,100)
count = 1
while count <= 5:
guess = int(raw_input("Guess an integer between 1 and 100 (inclusive): "))
if guess == number:
print "Correct! You won in",count,"guesses!"
break
if guess > number:
print "Lower!"
else:
print "Higher!"
count += 1
if count == 6:
print "Man, you really suck at this game. The number was", number