Question

我的脚本应该在表格中查找联系人并在屏幕上显示然后进行编辑。然而，这不是这种情况。我收到了错误解析错误：语法错误，第50行/home/admin/domains/domain.com.au/public_html/pick_modcontact.php中的意外$ end注意：这是此脚本中的最后一行。

<?
session_start();

if ($_SESSION[valid] != "yes") {
    header( "Location: contact_menu.php");
    exit;
} 

$db_name = "testDB";
$table_name = "my_contacts";
$connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error());
$db = @mysql_select_db($db_name, $connection) or die(mysql_error());

$sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name";

$result = @mysql_query($sql, $connection) or die(mysql_error());

$num = @mysql_num_rows($result);

if ($num < 1) {
    $display_block = "<p><em>Sorry No Results!</em></p>";
} else {
    while ($row = mysql_fetch_array($result)) {
        $id = $row['id'];
        $f_name = $row['f_name'];
        $l_name = $row['l_name'];
        $option_block .= "<option value\"$id\">$l_name, $f_name</option>";
    }
    $display_block = "<form method=\"POST\" action=\"show_modcontact.php\">
    <p><strong>Contact:</strong>
    <select name=\"id\">$option_block</select>
    <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p>
    </form>";
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Modify A Contact</title>
</head>

<body>
<h1>My Contact Management System</h1>
<h2><em>Modify a Contact</em></h2>
<p>Select a contact from the list below, to modify the contact's record.</p>
<? echo "$display_block"; ?>
<br>
<p><a href="contact_menu.php">Return to Main Menu</a></p>
</body>
</html>

Answer 1

你没有关闭第22行的} else {。

在关闭php部分之前，在}位之后添加</form>。

    </form>";
}
?>

Answer 2

“意外结束”，尤其是最后一行抛出的错误，通常意味着缺少大括号。

php MySQL语法错误

2 个答案: