new_img = convert(img, text);
(img, text) = convert_back(new_img);
有人可以用MATALB的内置图像来说明吗?
答案 0 :(得分:7)
我相信你正在寻找steganography。您可以从这个LSB steganography的MATLAB实现开始。
进行LSB隐写术的一种简单方法是采用无损压缩图像并设置每个分量(R,G,B)的LSB。然后,对于 m x n 图像,您将获得 3mn 位来存储信息。由于您正在修改LSB,因此差异不会是在图像中可以感知到。
<强>更新强>
所以我决定编写一个小而低效但具有示范性的例子:
function LSBStega
%%// Image and text
I = imread('coins.png');
text = 'Hello World etc';
assert(numel(I) > numel(text)*8,'Insufficient number of pixels');
%%// Encode
%// The end character signifies the end of the hidden text
end_char = '.';
%// Append it
text = [text end_char];
%// Convert each character into binary form with atleast 8 bits
%// We transpose it before calling (:) since the binary representation
%// is stores each character in binary per row and the (:) operations
%// vectorizes the matrix by column.
b = transpose(dec2bin(text,8));
%// Find which bits should be set to 1 or 0
ind_0 = find(b == '0');
ind_1 = find(b == '1');
%// Set the appropriate bits to 1 and 0 and leave the rest alone
I(ind_0) = bitset(I(ind_0),1,0);
I(ind_1) = bitset(I(ind_1),1,1);
%%// Faster decode
text_back = [];
for i = 1:8:numel(I)
%// Extract the LSB from a set of 8 bytes in the image
C = bitget(I(i:i+7),1);
%// Convert from binary to decimal
C = bin2dec(num2str(C));
%// Check if it's the end character; break if so, store if not
if(C == end_char)
break;
else
text_back(end+1) = C;
end
end
%// Convert to text
text_back = char(text_back);
%%// Display
subplot(1,2,1);
title('Original');
imshow(imread('coins.png'));
subplot(1,2,2);
title('Steganography Result');
imshow(I);
disp(text_back);
end