Google应用脚本 - 迭代文件夹和子文件夹

时间:2014-11-21 20:31:13

标签: javascript google-apps-script google-drive-api

我想使用谷歌应用程序脚本遍历Google云端硬盘中文件夹的树状结构。下面的代码列出了一些文件夹,但不是全部。你能建议什么是深入研究文件夹结构的最佳技术吗?我首先尝试记录所有文件夹名称。

谢谢。

function test() {
 listSubfolders(DriveApp.getFolderById('FOLDER_ID'));
}

function listSubfolders(parentFolder) {
  var childFolders = parentFolder.getFolders();

 while(childFolders.hasNext()) {
   Logger.log(childFolders.next().getName());
   listSubfolders(childFolders.next());   

 }


}

4 个答案:

答案 0 :(得分:7)

要访问子文件夹,您可以这样做,

function getSubFolders(parent) {
  parent = parent.getId();
  var childFolder = DriveApp.getFolderById(parent).getFolders();
  while(childFolder.hasNext()) {
    var child = childFolder.next();
    Logger.log(child.getName());
    getSubFolders(child);
  }
  return;
}

function listFolders() {
  var parentFolder = DriveApp.getFolderById("0B1n6YLYwFmK_dUpzRWhDRXNwdWc");
  var childFolders = parentFolder.getFolders();
  while(childFolders.hasNext()) {
    var child = childFolders.next();
    Logger.log(child.getName());
    getSubFolders(child);
  }
}

答案 1 :(得分:1)

这应该可以解决问题:

function start() {
 folder = DriveApp.getFolderById("0B_5HSTQXtXmsOHBzcnc2dTlkRFU") 
 listFolders(folder)
}

function listFolders(folder) {
  //starting point, we come here from start() or from the bottom of this function



  //check the name
  var name = folder.getName();

  if (name.match("TITL")) { 
     folder.addEditor("somePerson@gmail.com"); 
  }

  //now see if this folder has subfolders
  var subfolders = folder.getFolders();

  //if it has, we call this function again
  while (subfolders.hasNext()) {    
    listFolders(subfolders.next());
  }

}

答案 2 :(得分:1)

此Google脚本将生成包含所有文件和文件夹的Google云端硬盘树。

将此脚本复制到脚本编辑器。从“选择功能”菜单中选择功能“ genFolderTree”。将根文件夹名称“ RootDir”更改为函数genFolderTree()中的根目录

var foldername = 'RootDir';

Google脚本源代码-

function genFolderTree() {

  try {

  var foldername = 'RootDir';
  var folderlisting = 'TreeView_' + foldername;

  var parentFolder = DriveApp.getFoldersByName(foldername).next();


  var ss = SpreadsheetApp.create(folderlisting);
  var sheet = ss.getActiveSheet();
  var frontCell = [];
  sheet.appendRow([foldername]).getCurrentCell().setFontWeight('bold').setFontColor('red');
  frontCell.push(" ");
  getChildNode(parentFolder,sheet,frontCell);
  var files = parentFolder.getFiles();
  while (files.hasNext()) {
    frontCell.push(files.next().getName());
    sheet.appendRow( frontCell);
    frontCell.pop();
    }

  } catch (e) {

    Logger.log(e.toString());

  }

}


function getChildNode(parent,sheet,frontCell) {

  var childFolders = parent.getFolders();
  while (childFolders.hasNext()) {

    var childFolder = childFolders.next();

    frontCell.push(childFolder.getName())
    sheet.appendRow(frontCell);
    sheet.getRange(sheet.getLastRow(), frontCell.length).setFontWeight('bold').setFontColor('red');
    frontCell.pop();
    var files = childFolder.getFiles();
    frontCell.push(" ");
    var start_row = 0;
    var row_no = 0;
    while (files.hasNext()) {
      frontCell.push(files.next().getName());
      sheet.appendRow(frontCell);
      if(row_no==0){
        start_row = sheet.getLastRow();
      }
      row_no=row_no+1;
      frontCell.pop();
    }
    if(row_no>0){
      var range;
      range = sheet.getRange(start_row, frontCell.length,row_no);
      // The row grouping depth is increased by row_no.
      range.shiftRowGroupDepth(1);
    }

    // Recursive call for any sub-folders
    getChildNode(childFolder,sheet,frontCell);
    frontCell.pop();
  }

}

您可以从Github link

下载源

答案 3 :(得分:0)

认为这种方法可能不那么重复。这会以以下格式输出完整路径名:

'/Root/Directory/Directory/Directory/...'

“Logger”行所在的位置,您可以访问当前文件夹对象(callingFolder),因此此时您可以在该文件夹上插入任何操作。

function myFunction() {
  var topFolder = DriveApp.getFolderById("0AMBwhqwkCWBbUk9PVA");
  var topPath = "/";
  iterateSubFolders(topFolder, topPath);
}

function iterateSubFolders(callingFolder, callingPath) {

  var callingFolderName = callingFolder.getName();
  var callingFolderFullPath = callingPath + callingFolderName + "/";
  Logger.log(callingFolderFullPath);

  var childSubFolders = callingFolder.getFolders();
  while (childSubFolders.hasNext()) {
      var nextSubFolder = childSubFolders.next();
      iterateSubFolders(nextSubFolder, callingFolderFullPath);
  }
}