我有一个字符串数组pointAddress
,我想检查每个条目是否包含来自另一个数组的字符串validPointTypes
。
def pointAddress = ['bacnet://240101/AV:3', 'bacnet://240101/BV:9', 'bacnet://240101/AV:7', 'bacnet://240101/BALM:15']
def validPointTypes = ['AV', 'AI', 'AO', 'ANI', 'ANO', 'BV', 'BI', 'BO', 'BNI', 'BNO']
现在我只有一个巨大的if
声明。
j = pointName.size()
for(j=j-1; j>=0;j--) {
if(pointAddress[j]) {
if(pointAddress[j].contains('AV') || pointAddress[j].contains('AI') ||
pointAddress[j].contains('AO') || pointAddress[j].contains('ANI') ||
pointAddress[j].contains('ANO') || pointAddress[j].contains('BV') ||
pointAddress[j].contains('BI') || pointAddress[j].contains('BO') ||
pointAddress[j].contains('BNI') || pointAddress[j].contains('BNO')) {
} else {
pointAddress.remove(j)
pointName.remove(j)
m++
}
} else {
pointName.remove(j)
m++
}
}
必须有更好的方法,对吧?
答案 0 :(得分:34)
def valid = pointAddress.findAll { a ->
validPointTypes.any { a.contains(it) }
}
应该这样做