Question

您好，我需要一些帮助。我目前正在尝试创建一个搜索页面，用户可以通过书籍标题，类别，年份和出版商搜索特定图书

我已经创建了我的基本HTML搜索表单，这是以下代码：

<!DOCTYPE html>

<html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
    <title>Page Title</title>
</head>
<body>
<form id ="SearchPage" action="SearchPage.php" method="get">
<h1> Search Page</h1>

    Book Title <input type="text" name="bookTitle" />

    Category <select name="catDesc">
                <option value = "Business & Commerce">Business & Commerce</option>
                <option value = "Databases">Databases</option>
                <option value = "Databases and Web Development">Databases and Web Development</option>
                <option value = "Fiction">Fiction</option>
                <option value = "Flex & Flash Programming">Flex & Flash Programming</option>
                <option value = "Netorks">Netorks</option>
                <option value = "Programming">Programming</option>
                <option value = "Systems Design">Systems Design</option>
                <option value = "Web Development">Web Development</option>
            </select>



    Publisher <input type="text" name="pubName"/>

    Year <input type="text" name="bookYear"/>

    <input type ="submit" value-"Find Books"/>

</form>
</body>
</html>

这是我在下面做的PHP代码：

<!DOCTYPE HTML>
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
    <title>Search Page</title>
</head>
<body>
    <table>
     <tr>
     <th>Book Title</th>
     <th>Year</th>
     <th>Category</th>
     <th>Publisher</th>
     </tr>
<?php

include 'database_mysqli_conn.php';

$bookTitle = $_REQUEST['bookTitle'];
$bookYear =$_REQUEST['bookYear'];
$catDesc =$_REQUEST['catDesc'];
$pubName =$_REQUEST['pubName'];

$sql = "SELECT bookTitle, bookYear, catDesc, pubName, FROM nbc_book b inner join nbc_category c on b.catID = c.catID inner join nbc_publisher p on b.pubID = p.pubID WHERE 1";

$stmt = mysqli_prepare($conn, $sql);
    mysqli_stmt_execute($stmt);
    mysqli_stmt_bind_result($stmt, $bookTitle, $bookYear, $bookPrice, $catDesc);

if (!empty($bookTitle)) {

    $sql= $sql." AND bookTitle = '$bookTitle'";

    }

if (!empty($bookYear)) {

    $sql= $sql." AND bookYear = '$bookYear'";

}

if (!empty($catDesc)) {

    $sql= $sql." AND catDesc = '$catDesc'";

}

if (!empty($pubName)) {

    $sql= $sql." AND pubName = '$pubName'";

}

while (mysqli_stmt_fetch($stmt)){
    echo "<tr>
                <td>$bookTitle</td>
                <td>$bookYear</td>
                <td>$catDesc</td>
                <td>$pubName</td>
             </tr>";
}

mysqli_stmt_close($stmt);
mysqli_close($conn);

?>

</body>
</html>

问题是，这是我提交搜索时收到的错误消息：

警告：mysqli_stmt_execute（）要求参数1为mysqli_stmt，第27行/home/unn_w11036829/public_html/PHPexercises/SearchPage.php中给出布尔值

警告：mysqli_stmt_bind_result（）要求参数1为mysqli_stmt，布尔值在第28行的/home/unn_w11036829/public_html/PHPexercises/SearchPage.php中给出

警告：mysqli_stmt_fetch（）要求参数1为mysqli_stmt，第54行/home/unn_w11036829/public_html/PHPexercises/SearchPage.php中给出布尔值

警告：mysqli_stmt_close（）要求参数1为mysqli_stmt，第63行/home/unn_w11036829/public_html/PHPexercises/SearchPage.php中给出布尔值书名年份类别出版商

任何人都可以告诉我哪里出错了！过去一小时我一直坚持这一点，它让我疯了。

提前谢谢

Answer 1

您的查询准备失败，您未能检查失败等等......

$sql = "SELECT bookTitle, bookYear, catDesc, pubName, FROM nbc_book b inner join ..."
                                                    ^--- stray comma

从不 EVER 假设数据库查询成功。特别是在发展中。总是假设失败，检查失败，并将成功视为一个惊喜：

$stmt = mysqli_prepare($conn, $sql) or die(mysqli_error($conn));
                                   ^^^^^^^^^^^^^^^^^^^^^^^^^^^^

Answer 2

CHANGE

$sql = "SELECT bookTitle, bookYear, catDesc, pubName, FROM nbc_book b inner join nbc_category c on b.catID = c.catID inner join nbc_publisher p on b.pubID = p.pubID WHERE 1";

要

$sql = "SELECT bookTitle, bookYear, catDesc, pubName FROM nbc_book b inner join nbc_category c on b.catID = c.catID inner join nbc_publisher p on b.pubID = p.pubID WHERE 1";

注意pubName之后的逗号。

编辑：你应该包装你的mysqli_stmt_execute（$ stmt）在if中确保你正在捕捉这样的错误

if(mysqli_stmt_execute($stmt)){
 //YOUR CODE
}
else{
echo mysqli_stmt_error;
}

mysqli_stmt_execute（）期望参数1为mysqli_stmt，

2 个答案: