Question

在程序中，用户必须输入密码，如果他输入错误，程序将再次提示他2次，如果他没有正确，那么程序将会过期2次。我该怎么做呢到目前为止，这是我的计划......

password=input("Enter password:")
while password != 'cat': 
    print ("password is wrong, try it again")
    password= input ("Enter your password:")

print ("Password correct be happy")

Answer 1

慈善程序员

for trial in range(3):
    print ("Attempt no.",trial, end=" ")
    passw = input('.  Enter password > ')
    if passw == 'cat' : break
else:
    passw = 'cat'

是的，简陋的for循环还有一个else子句："Loop statements may have an else clause; it is executed when the loop terminates through exhaustion of the list (with for) or when the condition becomes false (with while), but not when the loop is terminated by a break statement."。

Answer 2

试试这个：

import sys
max_tries = 3; current_tries = 0
password=input("Enter password:")
while password != 'cat': 
    if current_tries > max_tries:
        print "too many tries"
        sys.exit(0)
    print ("password is wrong, try it again")
    password= input ("Enter your password:")
    current_tries +=1


print ("Password correct be happy")

Answer 3

max_tries = 3
password = None
for i in range(max_tries):
    password = input("Enter Password:")
    if password == "cat": break
if password != "cat": 
    print ("ERROR TOO MANY TRIES!")
else:
    print ("You Win!")

是一种简单的方法......

Python：如何让程序提示用户输入一定数量的固定时间？

3 个答案:

慈善程序员