Question

它应该说新记录然后我应该能够在项目表中看到新数据

与数据库文件的连接包含：

    $server="localhost";
    $login="root";
    $pass="";
    $database="floweritem";

    $con=mysqli_connect($server,$login,$pass,$database);
    if(mysqli_connect_errno()){
    echo "Failed connect to MYSQL".mysqli_connect_error();
    }

表格行动

PHP

    <?php
    if(isset($_POST['submit'])){
    $Name=mysqli_real_escape_string($con,$_POST['Name']);
    $Desc=mysqli_real_escape_string($con,$_POST['Desc']);
    $Size=mysqli_real_escape_string($con,$_POST['Size']);
    $Price=mysqli_real_escape_string($con,$_POST['Price']);


    //no problwm with connection to table or database
    $sql="INSERT INTO `items`(`Name`,`Description`,`Size`,`Price`) 
    VALUES($Name,$Desc,$Size,$Price)";
    echo $Desc;


    if(mysqli_query($con,$sql)){ 
    echo "new record";
    }
    //always get wrong
    //can't find problem
    else{echo"Wrong";}
    mysqli_close($con);
    }
    ?>

显示$ Desc但未成功在项目表中插入数据

Answer 1

新的PHP代码应该是这样的

<?php
    if(isset($_POST['submit'])){
    $Name=mysqli_real_escape_string($con,$_POST['Name']);
    $Desc=mysqli_real_escape_string($con,$_POST['Desc']);
    $Size=mysqli_real_escape_string($con,$_POST['Size']);
    $Price=mysqli_real_escape_string($con,$_POST['Price']);


    //no problwm with connection to table or database
    $sql="INSERT INTO `items`(`Name`,`Description`,`Size`,`Price`) 
    VALUES('$Name','$Desc','$Size','$Price')";
    echo $Desc;


    if(mysqli_query($con,$sql)){ 
    echo "new record";
    }
    //always get wrong
    //can't find problem
    else{echo"Wrong";}
    mysqli_close($con);
    }
    ?>

Answer 2

您需要针对值添加单引号。

更正代码：

 //no problwm with connection to table or database
    $sql="INSERT INTO `items`(`Name`,`Description`,`Size`,`Price`) 
    VALUES('$Name','$Desc','$Size','$Price')";
    echo $Desc;

否则，MySQL会将用户输入的值视为MySQL关键字，从而产生语法错误。

Answer 3

试试这个：

PHP：

<?php
    if(isset($_POST['submit'])){
    $Name=mysqli_real_escape_string($con,$_POST['Name']);
    $Desc=mysqli_real_escape_string($con,$_POST['Desc']);
    $Size=mysqli_real_escape_string($con,$_POST['Size']);
    $Price=mysqli_real_escape_string($con,$_POST['Price']);


    //no problwm with connection to table or database
    $sql="INSERT INTO `items`(`Name`,`Description`,`Size`,`Price`) 
    VALUES('$Name','$Desc','$Size','$Price')";
    echo $Desc;


    if(mysqli_query($con,$sql)){ 
    echo "new record";
    }
    //always get wrong
    //can't find problem
    else{echo"Wrong";}
    mysqli_close($con);
    }
    ?>

在数据库表中使用mysqli插入数据不起作用？连接工作正常

3 个答案: