Question

我正在制作一个PHP Google App Engine网站，我发现从Google Cloud服务请求图片会使页面加载速度极慢。

如果没有加载图片，页面加载需要大约0.5秒，图片需要10-15秒。我认为我做错了所以任何帮助都会非常感激。

我的代码

require_once "google/appengine/api/cloud_storage/CloudStorageTools.php";
use google\appengine\api\cloud_storage\CloudStorageTools;

...

function cloudStorageUrl($url, $size, $crop) {
    if (file_exists($url)) {
        $object_image_url = CloudStorageTools::getImageServingUrl($object_image_file, ['size' => $size, 'crop' => $crop]);
        return $object_image_url;
    }
    else {
        return false;
    }
}

Answer 1

正如Paul＆amp; amp; Stuart我通过在Google Cloud SQL中创建一个表来解决这个问题，我可以存储从Google Cloud Storage返回的URL，这样我就不必重复请求该URL。

代码示例

// Cloud Storage URL function
function cloudStorageUrl($url, $size, $crop) {
    if (file_exists($url)) {
        $object_image_url = CloudStorageTools::getImageServingUrl($object_image_file, ['size' => $size, 'crop' => $crop]);
        return $object_image_url;
    } else {
        return 'none';
    }
}

// Connect to database
$db = new pdo('mysql:unix_socket=/cloudsql/<your-project-id>:<your-instance-name>;dbname=guestbook', 'root', '');

foreach($db->query('SELECT * FROM `images` WHERE `id`="'.$id.'"') as $row) {
    // Check if Cloud Storage URL already exists
    if ($row['url'] && $row['url'] !== 'none') {
        $url = $row['url'];
    } else {
        // Get the Cloud Storage URL and save it
        $url = cloudStorageUrl($row['cloud_storage_location'], 400, false);
        $stmt = $db->prepare('INSERT INTO `images` (id, url) VALUES (:id, :url ON DUPLICATE KEY UPDATE url=VALUES(url))');
        $stmt->execute(array(':id' => intval($id), ':url' => htmlspecialchars($url)));
    }
}

从Google Cloud请求图片会使页面速度极慢

1 个答案: