Android日期在今天2天前发布,就像那样

时间:2014-11-21 07:50:57

标签: android jodatime

我需要像今天一样打印日期,昨天,2天前,就像我已经完成的那样 我得到的日期如下:String date1 = "Thu Nov 13 19:01:25 GMT+05:30 2014";str=get_userTime(date1);

一样打电话
private String get_userTime(String usertime) {
        Date d = null;

        // String datee = "Thu Nov 13 19:01:25 GMT+05:30 2014";
        String datee = usertime;
        SimpleDateFormat inputFormat = new SimpleDateFormat(
                "EE MMM dd HH:mm:ss zz yyy");

        try {
            d = inputFormat.parse(datee);
        } catch (java.text.ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        SimpleDateFormat outputFormat1 = new SimpleDateFormat("MM/dd/yyyy");
        System.out.println(outputFormat1.format(d));
         op = outputFormat1.format(d);
        op=formatToYesterdayOrToday(op);
        return op;

    }

这是昨天/今天我使用此Link

的另一项功能
public static String formatToYesterdayOrToday(String date) {
        date=op;
        DateTime dateTime = DateTimeFormat.forPattern("EEE hh:mma MMM d, yyyy")
                .parseDateTime(date);
        DateTime today = new DateTime();
        DateTime yesterday = today.minusDays(1);
        DateTimeFormatter timeFormatter = DateTimeFormat.forPattern("hh:mma");

        if (dateTime.toLocalDate().equals(today.toLocalDate())) {
            return "Today " + timeFormatter.print(dateTime);
        } else if (dateTime.toLocalDate().equals(yesterday.toLocalDate())) {
            return "Yesterday " + timeFormatter.print(dateTime);
        } else {
            return date;
        }
    }

但是得到错误:

11-21 13:12:10.626: E/AndroidRuntime(20654): java.lang.IllegalArgumentException: Invalid format: "11/21/2014"
11-21 13:12:10.626: E/AndroidRuntime(20654):    at org.joda.time.format.DateTimeFormatter.parseDateTime(DateTimeFormatter.java:871)

开启

DateTime dateTime = DateTimeFormat.forPattern("EEE hh:mma MMM d, yyyy")
                .parseDateTime(date); //In (formatToYesterdayOrToday())

我使用过Joda-time.jar

8 个答案:

答案 0 :(得分:3)

您可以尝试以下代码:( delta是以毫秒为单位的时间)

public static String getDisplayableTime(long delta)
{       
     long difference=0;
     Long mDate = java.lang.System.currentTimeMillis();     

     if(mDate > delta)
     {
         difference= mDate - delta;     
         final long seconds = difference/1000;
         final long minutes = seconds/60;
         final long hours = minutes/60;
         final long days = hours/24;
         final long months = days/31;
         final long years = days/365;

        if (seconds < 0)
        {
          return "not yet";
        }
        else if (seconds < 60)
        {
          return seconds == 1 ? "one second ago" : seconds + " seconds ago";
        }
        else if (seconds < 120)
        {
          return "a minute ago";
        }
        else if (seconds < 2700) // 45 * 60
        {
          return minutes + " minutes ago";
        }
        else if (seconds < 5400) // 90 * 60
        {
          return "an hour ago";
        }
        else if (seconds < 86400) // 24 * 60 * 60
        {
          return hours + " hours ago";
        }
        else if (seconds < 172800) // 48 * 60 * 60
        {
          return "yesterday";
        }
        else if (seconds < 2592000) // 30 * 24 * 60 * 60
        {
          return days + " days ago";
        }
        else if (seconds < 31104000) // 12 * 30 * 24 * 60 * 60
        {

          return months <= 1 ? "one month ago" : days + " months ago";
        }
        else
        {

          return years <= 1 ? "one year ago" : years + " years ago";
        }
    }
        return null;
}

答案 1 :(得分:3)

对于Android,您可以使用Joda-Time-Android库的最简单方式:

Date yourTime = new Date();
DateTime dateTime = new DateTime(yourTime); //or simple DateTime.now()
final String result = DateUtils.getRelativeTimeSpanString(getContext(), dateTime);

答案 2 :(得分:2)

DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
DateTime datetime = formatter.parseDateTime(time); // time = string time data

LocalDate localDate = new LocalDateTime(datetime).toLocalDate();
LocalDate localDateNow = new LocalDateTime().toLocalDate();

int diff = Days.daysBetween(localDate, localDateNow).getDays();

然后使用差异来评估哪一天。

答案 3 :(得分:2)

现在可以使用Android DateUtils中的方法轻松实现以下目的。

DateUtils.getRelativeTimeSpanString(feedItem.timeStamp)

您可以获得类似的输出,

1小时前, 昨天, 2天前

答案 4 :(得分:1)

在你的DateTimeFormatter中,它需要某种格式的日期,即"EEE hh:mma MMM d, yyyy"

DateTime dateTime = DateTimeFormat.forPattern("EEE hh:mma MMM d, yyyy")
            .parseDateTime(date);

但是你传递的是"MM/dd/yyyy"格式:

SimpleDateFormat outputFormat1 = new SimpleDateFormat("MM/dd/yyyy");
op = outputFormat1.format(d);
op = formatToYesterdayOrToday(op);

所以,你可以做的是改变你的DateTimeFormatter以期望你的初始格式"MM/dd/yyyy"

DateTime dateTime = DateTimeFormat.forPattern("MM/dd/yyyy")
            .parseDateTime(date);

这应该可以解决你得到的错误。我不知道最后整件事情是否能给你你想要的东西(&#34;今天&#34;,&#34;昨天&#34;,&#34; 2天前&#34; ,. ..)。

答案 5 :(得分:0)

我使用以下函数来获取RemainingTime,但格式几乎与您想要的相同。尝试此代码并根据您的要求进行更改。

/**
     * To convert expire time according to selected format(period) 
     * @param period
     * @return
     */
    public String getExpireDate(int period) {
        int days = 0, weeks = 0, hours = 0, mins = 0, secs = 0;
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

        Date systemDate = Calendar.getInstance().getTime();
        String myDate = sdf.format(systemDate);



        long millse = // your time in milliseconds
        if (millse < 0) {
            return activity.getResources().getString(R.string.already_expire);
        }
        long mills = Math.abs(millse);

        if (mills > 60480000) {
            weeks = (int) (mills / 604800000);
            mills = mills % 604800000;
            days = (int) (mills / 86400000);
            mills = mills % 86400000;
            hours = (int) (mills / 3600000);
            mills = mills % 3600000;
            mins = (int) (mills / 60000);
            mills = mills % 60000;
            secs = (int) (mills / 1000);
        } else if (mills > 86400000) {
            days = (int) (mills / 86400000);
            mills = mills % 86400000;
            hours = (int) (mills / 3600000);
            mills = mills % 3600000;
            mins = (int) (mills / 60000);
            mills = mills % 60000;
            secs = (int) (mills / 1000);
        } else if (mills > 3600000) {
            hours = (int) (mills / 3600000);
            mills = mills % 3600000;
            mins = (int) (mills / 60000);
            mills = mills % 60000;
            secs = (int) (mills / 1000);
        }
        String remainingTime = "";
        switch (period) {
        case SHORT_PERIOD:

            if (weeks > 0) {
                if (weeks == 1) {
                    remainingTime = weeks + " week";
                } else {
                    remainingTime = weeks + " weeks";
                }
            } else if (days > 0) {
                if (days == 1) {
                    remainingTime = days + " day";
                } else {
                    remainingTime = days + " days";
                }
            } else if (hours > 0) {
                if (hours == 1) {
                    remainingTime = hours + " hour";
                } else {
                    remainingTime = hours + " hours";
                }
            } else if (mins > 0) {
                if (mins == 1) {
                    remainingTime = mins + " minute";
                } else {
                    remainingTime = mins + " minutes";
                }
            } else {
                if (secs == 1) {
                    remainingTime = secs + " second";
                } else {
                    remainingTime = secs + " seconds";
                }

            }
            break;
        case DETAILED_PERIOD:
            if (weeks > 0) {
                remainingTime = (weeks * 7) + days + " days," + hours
                        + " hours," + mins + " minutes";// + secs + " secs";
            } else if (days > 0) {
                remainingTime = days + " days," + hours + " hours," + mins
                        + " minutes";// + secs + " seconds";
            } else if (hours > 0) {
                remainingTime = hours + " hours," + mins + " minutes";// + secs
                                                                        // +
                                                                        // " seconds";
            } else if (mins > 0) {
                remainingTime = mins + " minutes";// + secs + " seconds";
            }
            break;
        case EXACT_DATE_TIME:
            SimpleDateFormat target = new SimpleDateFormat("dd-MMM-yyyy");
            try {
                remainingTime = target.format(sdf.parse(taskData
                        .getTask_expire_date()));
            } catch (ParseException e) {
                e.printStackTrace();
            }
            break;
        default:
            break;
        }
        return remainingTime;
    }

答案 6 :(得分:0)

这应该提供你想要的输出。

  

使用SimpleDateFormat解析您的日期,然后使用以下date.getTime();

long now = System.currentTimeMillis();       
DateUtils.getRelativeTimeSpanString(your time in long, now, DateUtils.MINUTE_IN_MILLIS);

答案 7 :(得分:0)

假设您有这样的数据:

{"data":[{"id":"79tiyfjgdfg","sales_name":"Sengkuni","sales_branch":"Kingdom of Hastina","message":"Leader of Kurowo sent you a gold","timestamp":"2020-03-23 10:16:01"}]}

并调用如下函数:

holder.timestamp.setText(Utils.beautifyDate(context, notifications.get(position).getTimestamp(), "EEEE, MMMM d, YYYY"));

对于其他格式,您可以从https://developer.android.com/reference/java/text/SimpleDateFormat

查看

在下面使用此功能

public static String beautifyDate(Context context, String timestamp, String formatDate) {

    String beautifyFormat;

    SimpleDateFormat fmt = new SimpleDateFormat("yyyy-M-dd H:mm:ss", Locale.getDefault());
    Date date = new Date();

    try {
        date = fmt.parse(timestamp);
    } catch (Exception e) {
        e.printStackTrace();
    }

    String mYear = new SimpleDateFormat("yyyy", Locale.getDefault()).format(date);
    String mMonth = new SimpleDateFormat("M", Locale.getDefault()).format(date);
    String mDay = new SimpleDateFormat("dd", Locale.getDefault()).format(date);
    String mHour = new SimpleDateFormat("H", Locale.getDefault()).format(date);
    String mMinutes = new SimpleDateFormat("mm", Locale.getDefault()).format(date);

    Calendar now = Calendar.getInstance();
    int years = now.get(Calendar.YEAR);
    int months = now.get(Calendar.MONTH) + 1;
    int days = now.get(Calendar.DATE);
    int hours = now.get(Calendar.HOUR_OF_DAY);
    int minutes = now.get(Calendar.MINUTE);

    if (mYear.equals(String.valueOf(years)) && mMonth.equals(String.valueOf(months)) && mDay.equals(String.valueOf(days))) {
        Log.i("timestamp", "on same day");
        hours -= Integer.parseInt(mHour);

        beautifyFormat = hours > 1 ? hours + " " + context.getString(R.string.hours_ago): hours + " " + context.getString(R.string.hour_ago);

        if (hours == 0) {
            minutes -= Integer.parseInt(mMinutes);
            beautifyFormat = minutes > 1 ? minutes + " " + context.getString(R.string.minutes_ago): context.getString(R.string.moments_ago);
        }
    } else {
        days = now.get(Calendar.DATE) - Integer.parseInt(mDay);

        if (days == 1) {
            beautifyFormat = context.getString(R.string.tomorrow);
        } else {
            beautifyFormat = new SimpleDateFormat(formatDate, Locale.getDefault()).format(date);
        }
    }

    return beautifyFormat;
}

只需调整您希望能够看到今天或明天以及其他时间的结果的时间

希望它有用。