Question

我正在努力使用此代码超过12个小时，任何帮助都将深表感谢。在我发布代码之前几句话。我的后台身份验证代码非常相似，现在我正在进行站点成员身份验证。后台工作正常，前端没有。

这是CodeIgniter应用程序，是我做过很多次的事情。如果后端代码不起作用，我怀疑服务器有不同的设置，但后端代码工作。我不是ci的初学者，我想我在某个地方做了一些愚蠢的错误......

这是登录功能：

public function loginCheck()
    {     
        // set the validation rules
        $this->form_validation->set_rules('memberusername', 'Username', 'required|trim|encode_php_tags');
        $this->form_validation->set_rules('memberpassword', 'Password', 'required|trim|encode_php_tags');
        $this->form_validation->set_error_delimiters('<br /><p class=jsdiserr>', '</p><br />');
        // if validation is passed

        if ($this->form_validation->run() != FALSE) 
        {


            $this->db->where('memberUserName', $this->input->post('memberusername'));
            $this->db->where('memberOldPassword', strtoupper(md5("EBOSS/".$this->input->post('memberpassword')."/EBOSS")));
            $query = $this->membersModel->get();
            if($query)
            {

                $data = array(
                    'memberID'                      => $query[0]['memberID'],
                    'memberUserName'                => $query[0]['memberUserName'],
                    'memberOldPassword'             => $query[0]['memberOldPassword'],
                    'memberEmail'                   => $query[0]['memberEmail'],
                    'isUserLoggedIn' => TRUE
                );           
                $currentUser = array();
                //echo "Here after the data?";
                //die();
               $this->session->set_userdata('currentMember', $data);
                $currentMember = $this->session->userdata('currentMember');
               // print_r($currentMember);
                //die();

                echo json_encode(array("success" => true));
        } else {   
                echo json_encode(array("success" => false, "error" => "Wrong credentials"));
        }
        //  form validation has failed 
        } else {     
            $errorMessage = "Wrong Username or passwrod!";
        }
    }   // end of function loginCheck

这是javascript代码：

// user fill both fields, user name and memberpassword, so form can be submitted
   jQuery("#formLogin").submit(function(e){     
       e.preventDefault();

        var memberusername = jQuery(this).find("#memberusername").val();
        var memberpassword = jQuery(this).find("#memberpassword").val();
        var obj = {memberusername: memberusername, memberpassword: memberpassword};
        var url = jQuery(this).attr("action");
        jQuery.post(url, obj, function(r){
            if(r.success) window.location.replace('http://www.example.net/memberAccount/memberDashboard'); 
            else  jQuery('#errorMessageTop').fadeIn();
        }, 'json')
   })

我收到错误Uncaught TypeError：无法读取null

的属性“success”

最后，这是用户帐户页面上的输出：

Array
(
[session_id] => 711a8349fe7414802928ac27b7bd2c4f
[ip_address] => 62.103.42.2
[user_agent] => Mozilla/5.0 (Windows NT 6.1; rv:33.0) Gecko/20100101 Firefox/33.0
[last_activity] => 1416509476
[currentUser] => Array
    (
        [authbackofficeuserID] => 428
        [authbackofficeuserUserName] => mysuername
        [authbackofficeuserPassword] => 69e3184e2cdc3605693ba24887c519aaafc89477
        [authbackofficeuserEmail] => me@mail.com
        [authbackofficeuserFirstName] => My
        [authbackofficeuserLastName] => Name
        [isUserLoggedIn] => 1
    )

)

当前用户是在后台办公室登录的用户数据，但无法找到应该在这里的currentMember。

事情更奇怪，如果我注释掉javascript，数据会显示在数组输出中。一旦我删除评论，并且我退出，当我再次尝试登录时，该数据（currentMember）就消失了。

任何帮助都将深受赞赏。

问候，约翰

Answer 1

我认为您错过了 $ query-＆gt; result_array（）;

$members = $query->result_array();

if(count($members) != 0){
 //set your session logic here
}

记得使用MVC;我看到你正在混合 $ this-＆gt; db 函数（Model）和 $ this-＆gt; form_validation 函数（Controller）

if ($this->form_validation->run() != FALSE) {
        $this->db->where('memberUserName', $this->input->post('memberusername'));
        $this->db->where('memberOldPassword', strtoupper(md5("EBOSS/".$this->input->post('memberpassword')."/EBOSS")));
        $query = $this->membersModel->get();
        $members = $query->result_array();

        if(count($members) != 0){
            $data = array(
                'memberID'                      => $members[0]['memberID'],
                'memberUserName'                => $members[0]['memberUserName'],
                'memberOldPassword'             => $members[0]['memberOldPassword'],
                'memberEmail'                   => $members[0]['memberEmail'],
                'isUserLoggedIn' => TRUE
            );
            $this->session->set_userdata('currentMember', $data);
            echo json_encode(array("success" => true));
        }else {
            echo json_encode(array("success" => false, "error" => "Wrong credentials"));
        }

} else {     
    echo json_encode(array("success" => false, "error" => "Incorrect inputs"));
}

并检查 memberDashboard 控制器以获取会话

在jquery重定向之后，codeigniter会话数据丢失

1 个答案: