我想在脚本运行后清除一些目录,删除当前目录中的某些文件夹和文件(如果存在)。最初,我构建了这样的脚本:
if (Test-Path Folder1) {
Remove-Item -r Folder1
}
if (Test-Path Folder2) {
Remove-Item -r Folder2
}
if (Test-Path File1) {
Remove-Item File1
}
现在我已经在本节列出了很多项目,我想清理代码。我怎么能这样做?
附注:在脚本运行之前,项目已经清理,因为它们是从上一次运行中遗留下来的,以防我需要检查它们。
答案 0 :(得分:11)
# if you want to avoid errors on missed paths
# (because even ignored errors are added to $Error)
# (or you want to -ErrorAction Stop if an item is not removed)
@(
'Directory1'
'Directory2'
'File1'
) |
Where-Object { Test-Path $_ } |
ForEach-Object { Remove-Item $_ -Recurse -Force -ErrorAction Stop }
答案 1 :(得分:1)
Folder1, Folder2, File1, Folder3 |
?{ test-path $_ } |
%{
if ($_.PSIsContainer) {
rm -rec $_ # For directories, do the delete recursively
} else {
rm $_ # for files, just delete the item
}
}
或者,您可以为每种类型执行两个单独的块。
Folder1, Folder2, File1, Folder3 |
?{ test-path $_ } |
?{ $_.PSIsContainer } |
rm -rec
Folder1, Folder2, File1, Folder3 |
?{ test-path $_ } |
?{ -not ($_.PSIsContainer) } |
rm
答案 2 :(得分:0)
一种可能性
function ql {$args}
ql Folder1 Folder2 Folder3 File3 |
ForEach {
if(Test-Path $_) {
Remove-Item $_
}
}
答案 3 :(得分:0)
# if you do not mind to have a few ignored errors
Remove-Item -Recurse -Force -ErrorAction 0 @(
'Directory1'
'Directory2'
'File1'
)