Question

我想知道你们是否可以在我的应用上帮助我。对于那些我缺少的人来说，这真的很容易。我正在尝试链接一个布局上的按钮以导航到其他布局。这六个按钮应该分为六种不同的布局......

按钮7应转到布局Number7 我已经做了按钮1，它适用于number1。

这是布局的屏幕截图，这是我的main.java的代码：http://imgur.com/zLJ3cdE

package com.example.isthisyourluckyday;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;

public class Main extends Activity {
   /** Called when the activity is first created. */
   @Override
   public void onCreate(final Bundle savedInstanceState) {
          super.onCreate(savedInstanceState);
          setContentView(R.layout.main);
          final Button b = (Button) findViewById(R.id.button1);

          b.setOnClickListener(new OnClickListener() {

                 @Override
                 public void onClick(View v) {
                       // TODO Auto-generated method stub
                       startActivity(new Intent(Main.this, Number1.class));

                 }
          });
   }
}

另外...... ..这里是number7.java，应链接到number7布局

package com.example.isthisyourluckyday;

import android.app.Activity;
import android.os.Bundle;
import android.widget.Button;

public class Number7 extends Activity {
                                             Button button7;
                                             @Override
                                             protected void onCreate(Bundle savedInstanceState) {
                                                   // TODO Auto-generated method stub
                                                   super.onCreate(savedInstanceState);
                                                   setContentView(R.layout.number7);
}}

如果你们能帮助我，我真的很感激。

Answer 1

如果第一个按钮有效，那么其他按钮的问题在哪里？

下面是所有代码：

public class Main extends Activity implements View.OnClickListener {

private final Button button1;
private final Button button2;
private final Button button3;
private final Button button4;
private final Button button5;
private final Button button6;
private final Button button7;

/** Called when the activity is first created. */
@Override
public void onCreate(final Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    button1 = (Button) findViewById(R.id.button1);
    button2 = (Button) findViewById(R.id.button2);
    button3 = (Button) findViewById(R.id.button3);
    button4 = (Button) findViewById(R.id.button4);
    button5 = (Button) findViewById(R.id.button5);
    button6 = (Button) findViewById(R.id.button6);
    button7 = (Button) findViewById(R.id.button7);

    button1.setOnClickListener(this);
    button2.setOnClickListener(this);
    button3.setOnClickListener(this);
    button4.setOnClickListener(this);
    button5.setOnClickListener(this);
    button6.setOnClickListener(this);
    button7.setOnClickListener(this);
}

@Override
public void onClick(View v) {
    if(v.equals(button1))
        startActivity(new Intent(Main.this, Number1.class));
    else if(v.equals(button2))
        startActivity(new Intent(Main.this, Number2.class));
    else if(v.equals(button3))
        startActivity(new Intent(Main.this, Number3.class));
    else if(v.equals(button4))
        startActivity(new Intent(Main.this, Number4.class));
    else if(v.equals(button5))
        startActivity(new Intent(Main.this, Number5.class));
    else if(v.equals(button6))
        startActivity(new Intent(Main.this, Number6.class));
    else if(v.equals(button7))
        startActivity(new Intent(Main.this, Number7.class));

}
}

Main类可以实现OnClickListener只有一个onClick（）函数。

Answer 2

我没有正确测试，但你明白了。它与其他答案类似，但我认为代码更清晰，重复次数更少。

package com.example.isthisyourluckyday;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;

public class Main extends Activity implements View.OnClickListener {

    final Button[] buttons = new Button[7];
    final Class[] classes = { Number1.class, Number3.class,  Number3.class,  
            Number4.class,  Number5.class,  Number6.class,  Number7.class };

    /** Called when the activity is first created. */
    @Override
    public void onCreate(final Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        buttons[0] = (Button) findViewById(R.id.button1);
        buttons[1] = (Button) findViewById(R.id.button2);
        buttons[2] = (Button) findViewById(R.id.button3);
        buttons[3] = (Button) findViewById(R.id.button4);
        buttons[4] = (Button) findViewById(R.id.button5);
        buttons[5] = (Button) findViewById(R.id.button6);
        buttons[6] = (Button) findViewById(R.id.button7);

        for(Button b : buttons){
            b.setOnClickListener(this);
        }
    }

    @Override
    public void onClick(View v) {
        for(int i=0; i<buttons.length; i++){
            if(buttons[i].equals(v)){
                Intent intent = new Intent(Main.this, classes[i]);
                startActivity(intent);
            }
        }
    }
}

Answer 3

当你开始这样的活动时 startActivity（new Intent（Main.this，Number1.class））; 你告诉Android开始Number1活动。因此，如果您想开始另一项活动，您只需做同样的事情：

final Button b7 = (Button) findViewById(R.id.button7);    
b7.setOnClickListener(new OnClickListener() {
  @Override
  public void onClick(View v) {
    startActivity(new Intent(Main.this, Number7.class));
  }
});

这不是很优雅，但可以解决问题。

你也可以在每个按钮上定义一个“标签”，如

<Button
        android:id="@+id/button1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:tag="1"
        android:onClick="choose"/>

然后在你的活动中添加一个方法

public void choose(View view) {
        String number = view.getTag().toString();
        Intent intent=new Intent();
        intent.setComponent(new ComponentName("com.example.isthisyourluckyday", "com.example.isthisyourluckyday.Number"+number));
        startActivity(intent);
    }

如何将这些按钮链接到其布局？

3 个答案: