Question

我已经编写了一个程序来从Eclipse中的XML文件中获取数据，并且我已经打印到文本视图以确保尝试正常，但它没有传递数据，但我不确定我是否得到了错误的参数，或者我称它为错误，所以任何帮助都会非常感激。

public class AnimalList extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_animal_list);

    //pulls data from XML file
    XmlPullParserFactory pullParserFactory;
    try 
    {
        pullParserFactory = XmlPullParserFactory.newInstance();
        XmlPullParser parser = pullParserFactory.newPullParser();

            InputStream in_s = getApplicationContext().getAssets().open("animals.xml");
            parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
            parser.setInput(in_s, null);

            parseXML(parser);

            TextView display = (TextView)findViewById(R.id.animalInfo);
            display.setText("crap");

    } 
    catch (XmlPullParserException e) 
    {
        e.printStackTrace();


    } 
    catch (IOException e) 
    {
        //Auto-generated catch block
        e.printStackTrace();


    }
}

我知道上面的工作是通过打印到文本视图，但接下来我有

private void parseXML(XmlPullParser parser) throws XmlPullParserException,IOException
{
    ArrayList<Animal> animals = new ArrayList<Animal>();
    int eventType = parser.getEventType();
    Animal currentAnimal = null;


    while (eventType != XmlPullParser.END_DOCUMENT)
    {

        String name = null;
        switch (eventType)
        {
            case XmlPullParser.START_DOCUMENT:
                //animals = new ArrayList();
                break;
            case XmlPullParser.START_TAG:
                name = parser.getName();
                if (name == "animal")
                {
                    currentAnimal = new Animal();
                } 
                else if (currentAnimal != null)
                {
                    if (name == "specificLocation")
                    {
                        currentAnimal.specificLocation = parser.nextText();
                    } 
                    else if (name == "name"){
                        currentAnimal.name = parser.nextText();
                    } 
                    else if (name == "location")
                    {
                        currentAnimal.location= parser.nextText();
                    }  
                    else if (name == "image")
                    {
                        currentAnimal.image= parser.nextText();
                    }  
                    else if (name == "animalInfo")
                    {
                        currentAnimal.animalInfo= parser.nextText();
                    }  
                    else if (name == "todaysFeed")
                    {
                        currentAnimal.todaysFeed= parser.nextText();
                    }  
                }
                break;
            case XmlPullParser.END_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase("animal") && currentAnimal != null){
                    animals.add(currentAnimal);
                } 
        }
        eventType = parser.next();
    }

    printAnimals(animals);
}

然后其中的代码没有做任何事情，所以希望有人能指出我是否正确传递了它？在第二个内部，它只是将数据放入一个数组中，但如果我在进行任何操作之前输入文本视图输出，它就没有做任何让我觉得它没有传递数据的事情

感谢。

Answer 1

搜索标记名称您已比较引用，但不比较字符串。它的工作正常。所以parseXML就是这样的：

private void parseXML(XmlPullParser parser) throws XmlPullParserException,IOException
{
    ArrayList<Animal> animals = new ArrayList<Animal>();
    int eventType = parser.getEventType();
    Animal currentAnimal = null;


    while (eventType != XmlPullParser.END_DOCUMENT)
    {

        String name = null;
        switch (eventType)
        {
            case XmlPullParser.START_DOCUMENT:
                //animals = new ArrayList();
                break;
            case XmlPullParser.START_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase( "animal"))
                {
                    currentAnimal = new Animal();
                } 
                else if (currentAnimal != null)
                {
                    if (name.equalsIgnoreCase( "specificLocation"))
                    {
                        currentAnimal.specificLocation = parser.nextText();
                    } 
                    else if (name .equalsIgnoreCase( "name")){
                        currentAnimal.name = parser.nextText();
                    } 
                    else if (name .equalsIgnoreCase( "location"))
                    {
                        currentAnimal.location= parser.nextText();
                    }  
                    else if (name .equalsIgnoreCase( "image"))
                    {
                        currentAnimal.image= parser.nextText();
                    }  
                    else if (name .equalsIgnoreCase(  "animalInfo"))
                    {
                        currentAnimal.animalInfo= parser.nextText();
                    }  
                    else if (name .equalsIgnoreCase(  "todaysFeed"))
                    {
                        currentAnimal.todaysFeed= parser.nextText();
                    }  
                }
                break;
            case XmlPullParser.END_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase("animal") && currentAnimal != null){
                    animals.add(currentAnimal);
                } 
        }
        eventType = parser.next();
    }

    printAnimals(animals);
}

希望它有帮助:) 马尔钦

Android Java传递XML解析器

1 个答案: