Question

大家好我有以下XML文件：

＆＃13;

<?xml version="1.0" encoding="utf-8" ?>
<products siteID="629">
  <product id="14321904">
    <name>Taior, negru</name>
    <description3>
      <ul>
        <li>articol de damă</li>
        <li>decolteu în V</li>
        <li>inserţii din piele eco</li>
        <li>închidere cu un singur nasture</li>
        <li>material: decolteu în V</li>
        <li>inserţii din piele eco</li>
        <li>închidere cu un singur nasture</li>
      </ul>
    </description3>
    <material>100% poliester</material>
    <ModelSizingDescr/>
    <Measurements/>
    <SupplierColor/>
  </product>
  <product id="14321905">
    <name>Taior, negru</name>
    <description3>
      <ul>
        <li>articol de damă</li>
        <li>decolteu în V</li>
        <li>inserţii din piele eco</li>
        <li>închidere cu un singur nasture</li>
        <li>material: decolteu în V</li>
        <li>inserţii din piele eco</li>
        <li>închidere cu un singur nasture</li>
      </ul>
    </description3>
    <material>100% poliester</material>
    <ModelSizingDescr/>
    <Measurements/>
    <SupplierColor/>
  </product>

＆＃13;

我对XSLT有点生疏，并且没有设法做很多事情。我想要的是摆脱<li>标签中的重复文本（我在某种程度上设法做到了）。其次，我想将此行<li>material: decolteu în V</li>替换为节点中的内容，因此它看起来像<li>material: 100% poliester</li>。要将处理完毕的XML文件包装起来，应该如下所示：

＆＃13;

<products siteID="629">
  <product id="14321904">
    <name>Taior, negru</name>
    <description3>
      <ul>
        <li>articol de damă</li>
        <li>decolteu în V</li>
        <li>inserţii din piele eco</li>
        <li>închidere cu un singur nasture</li>
        <li>material: 100% poliester</li>
      </ul>
    </description3>
    <material>100% poliester</material>
    <ModelSizingDescr/>
    <Measurements/>
    <SupplierColor/>
  </product>

＆＃13;

欢迎任何想法和建议，谢谢！

Answer 1

假设您在输出中需要两个产品。和xsl v1.0

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="li">
        <xsl:if test="not(node()) or not(preceding-sibling::node()[.=string(current())])">
            <xsl:copy>
                <xsl:apply-templates/>
            </xsl:copy>
        </xsl:if>
    </xsl:template>
    <xsl:template match="li/text()[.='material: decolteu în V']">material: 100% poliester</xsl:template>
</xsl:stylesheet>

当应用于输入时，响应将是

 <?xml version="1.0" encoding="UTF-8"?>
<products siteID="629">
    <product id="14321904">
        <name>Taior, negru</name>
        <description3>
            <ul>
                <li>articol de damă</li>
                <li>decolteu în V</li>
                <li>inserţii din piele eco</li>
                <li>închidere cu un singur nasture</li>
                <li>material: 100% poliester</li>
            </ul>
        </description3>
        <material>100% poliester</material>
        <ModelSizingDescr/>
        <Measurements/>
        <SupplierColor/>
    </product>
    <product id="14321905">
        <name>Taior, negru</name>
        <description3>
            <ul>
                <li>articol de damă</li>
                <li>decolteu în V</li>
                <li>inserţii din piele eco</li>
                <li>închidere cu un singur nasture</li>
                <li>material: 100% poliester</li>
            </ul>
        </description3>
        <material>100% poliester</material>
        <ModelSizingDescr/>
        <Measurements/>
        <SupplierColor/>
    </product>
</products>

Answer 2

如果您的处理器支持XSLT 2.0，您可以执行以下操作：

XSLT 2.0

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="ul">
    <xsl:for-each select="distinct-values(li)[not(starts-with(., 'material:'))]">
        <li><xsl:value-of select="."/></li>
    </xsl:for-each>
    <li>
        <xsl:value-of select="concat('material:', ../../material)"/>
    </li>
</xsl:template>

</xsl:stylesheet>

应用于您的示例（在纠正其格式良好之后！），结果：

<?xml version="1.0" encoding="UTF-8"?>
<products siteID="629">
   <product id="14321904">
      <name>Taior, negru</name>
      <description3>
         <li>articol de damă</li>
         <li>decolteu în V</li>
         <li>inserţii din piele eco</li>
         <li>închidere cu un singur nasture</li>
         <li>material:100% poliester</li>
      </description3>
      <material>100% poliester</material>
      <ModelSizingDescr/>
      <Measurements/>
      <SupplierColor/>
   </product>
   <product id="14321905">
      <name>Taior, negru</name>
      <description3>
         <li>articol de damă</li>
         <li>decolteu în V</li>
         <li>inserţii din piele eco</li>
         <li>închidere cu un singur nasture</li>
         <li>material:100% poliester</li>
      </description3>
      <material>100% poliester</material>
      <ModelSizingDescr/>
      <Measurements/>
      <SupplierColor/>
   </product>
</products>

需要eshop XML转换

2 个答案: