Question

import java.util.Scanner;

public class Ex7_3 {

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.println("This program that reads the integers between 1 and 100 and counts the occurrences of each");
    int [] counts = new int [101];
    System.out.println("Enter the integers between 1 and 100:");
    int next = input.nextInt();
    while (next != 0){
        if(next >= 1 && next<= 100)
            counts [next]++;
        next = input.nextInt();

    for(int i =0; i< counts.length;i++)
        for(int j = 0; j <= 100; j++)
            if(counts[next] > 1){
                System.out.println(next + "occurs" + j + "times");

        }
    }
}
}

解决方案应该是这样的吗？

输入1到100之间的整数：2 5 6 5 4 3 23 43 2 0 2发生2次 3发生1次 4发生1次 5次发生2次 6次发生1次 23次发生1次 43次出现

Answer 1

你的循环对我来说没有多大意义。你可能想要这样的东西

Scanner input = new Scanner(System.in);
System.out.println("This program that reads the integers between 1 and 100 and counts the occurrences of each");
int [] counts = new int [101];
System.out.println("Enter the integers between 1 and 100:");
int next = input.nextInt();
while (next != 0){
    if(next >= 1 && next<= 100)
        counts [next]++;
    next = input.nextInt();
}

// Here's the change
for (int i = 0; i < counts.length; i++) {
    if (counts[i] > 0) {
        System.out.println(i + " occurs " + counts[i] + " times.");
    }
}

为什么当我输入10个数字后运行这个程序时，它给我第一个数字出现100次？

1 个答案: