Question

我有一个对象数组

说，

var fruits = [
   {name:'apple', capital:'sample'},
   {name:'Tomato', capital:'sample'},
   {name:'jack fruit', capital:'sample'},
   {name:undefined, capital:'sample'},
   {name:'onion', capital:'sample'},
   {name:'Mango', capital:'sample'},
   {name:'Banana', capital:'sample'},
   {name:'brinjal', capital:'sample'}
];

我需要按名称

按升序对数组进行排序

该对象可能包含名称

未定义

对象名称可能是大写和小写的混合（所以必须是一个案例不敏感的搜索）

如果数组具有未定义，则应将该对象推送到已排序列表的末尾。

预期输出

var fruits = [
   {name:'apple', capital:'sample'},
   {name:'Banana', capital:'sample'},
   {name:'brinjal', capital:'sample'},
   {name:'jack fruit', capital:'sample'},
   {name:'Mango', capital:'sample'},
   {name:'onion', capital:'sample'},
   {name:'Tomato', capital:'sample'},
   {name:undefined, capital:'sample'}
];

Answer 1

fruits.sort(function (a, b) {
  // for all false values null, false, '', 0, and so on 
  //if (!a.name) return 1;
  //if (!b.name) return 0;

  // only for undefined 
  if (typeof (a.name) === 'undefined') return 1;
  if (typeof (b.name) === 'undefined') return 0;

  a = (a.name || '').toLowerCase();
  b = (b.name || '').toLowerCase(); 

  return (a > b) ? 1 : ((a < b) ? -1 : 0);
});

console.log(fruits);

DEMO：http://jsbin.com/hugise/3/

Javascript Case Insensitive对包含未定义值的对象进行排序

1 个答案: