Question

我的表workitem包含ticketNo，owner，status，subject和message列，我想要每张票数用户处于每个状态。我的查询返回以下结果：

  Owner    Status       Count      
  Daniel   Open         2
  Daniel   InProgress   5
  Daniel   Completed    10
  Moorthi  Open         2
  Moorthi  InProgress   2
  Moorthi  OnHold       5
  Moorthi  Competed     7

但我正在寻找如下结果：

  Owner    Status       Count
  Daniel   Open         3
  Daniel   InProgress   5
  Daniel   Completed    10
  Daniel   OnHold       0
  Daniel   Review       0
  Moorthi  Open         2
  Moorthi  InProgress   2
  Moorthi  OnHold       5
  Moorthi  Competed     7
  Moorthi  Review       0

我的查询：

select owner, Status, COUNT(status) from workitems 
group by Owner, Status order by  Owner, Status

Answer 1

SELECT所有者，sum（[Open]）为[Open]，sum（[Closed]）为[Closed]，sum（[InProgress]）为[InProgress]，sum（[Review]）为[Review] 来自工作项目 PIVOT（计数（状态） FOR status IN（[Open]，[Closed]，[InProgress]，[Review]））AS PVTTable 按所有者分组

sqlfiddle http://sqlfiddle.com/#!3/aa4d0/30

Answer 2

尝试以下：

选择 TEMP1.owner， TEMP1.status， COUNT（w.subject）从（选择 DISTINCT所有者， TEMP.status 从 #workitem 交叉申请（选择＆＃39;打开＆＃39; AS状态 UNION ALL SELECT＆＃39; InProgress＆＃39; UNION ALL SELECT＆＃39;已完成＆＃39; UNION ALL SELECT＆＃39; OnHold＆＃39; UNION ALL 选择＆＃39;评论＆＃39;）AS TEMP ）AS TEMP1 LEFT JOIN #workitem w 上 TEMP1.owner = w.owner AND TEMP1.status = w.status 通过...分组 TEMP1.owner， TEMP1.status 订购 TEMP1.owner

使用sql的每个用户的票数

2 个答案: