如何获得SQL Server中两个日期之间的秒数？

Question

我有这个MySQL代码

DELETE FROM UserError WHERE UNIX_TIMESTAMP() - UNIX_TIMESTAMP(date) > 86400

SQL Server中的这个MySQL代码等同于什么？

Answer 1

你可以使用datediff

DELETE FROM UserError WHERE 
Datediff(s, [date], getdate()) > 86400

Answer 2

试试这个：

SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000'); 

--Syntax
       DATEDIFF ( datepart , startdate , enddate )

Answer 3

您可以使用DateDiff。它看起来像这样：

DateDiff(datePart,startDate,endDate)

Answer 4

DATEDIFF ( ss , startdate , enddate )