在Firebug中的参数列表后继续获取SyntaxError：missing）

Question

我是编程新手，刚开始学习JavaScript。当试图创建一个对象打印出来时，Firebug不断给我一些错误代码

  参数列表

之后

SyntaxError：missing）

这是什么意思？我的代码中没有发现问题。

var player1 = {
    name: "fred",
    score: 1000,
    rank: 1
};
var player2 = {
    name: "Sam",
    score: 10000000,
    rank: 5
};

function playerDetails() {
    console.log(this.name + "has a rank of" this.rank + "and a score of" + this.score);
};
player1.logDetails = playerDetails();
player2.logDetails = playerDetails();
player1.logDetails();

Answer 1

首先。尝试更轻松的事情。

var player1 = { name:"fred", score: 1000, rank: 1 };
var player2 = { name: "Sam", score:10000000, rank: 5 };

function playerDetails (player) {

console.log(player.name + "has a rank of" + player.rank + "and a score of" + player.score);

};

playerDetails(player1);
playerDetails(player2);