Question

我有一个很长的字符串，我试图从中捕获2个值。我原来的字符串：

$string = 'content' => '{"sender":"xxx.xxx@icloud.com","location":"Beacon","event":"LocationTest","time":"2014-11-20 03:24:19 +0000"}',
             'auto_upgrade' => 1,
             'max_memory_size' => 262144

我想拥有位置＆＃34; Beacon＆＃34;在名为$location的var和事件＆＃34; LocationTest＆＃34;在名为$event的var中标题＆＃34; location＆＃34;：和＆＃34; event＆＃34;：将始终出现在我的字符串中。用正则表达式做任何简单的方法吗？

Answer 1

您可以使用

形式的正则表达式

位置：

/(?<="location":)"[^"]*"/

for event

/(?<="event":)"[^"]*"/

示例代码：

$str='"sender":"xxx.xxx@icloud.com","location":"Beacon","event":"LocationTest","time":"2014-11-20
03:24:19 +0000"';

$str =~ m/(?<="location":)("[^"]*")/;
print 'Location ',$1;
$str =~ m/(?<="event":)("[^"]*")/;
print 'event ',$1;

会产生输出

Location "Beacon"
event "LocationTest"

Answer 2

(?<=location":")([^"]+)|(?<=event":")([^"]+)

试试这个。参见demo.Grab捕获。

http://regex101.com/r/lZ5mN8/40

Answer 3

这看起来像JSON，这意味着通过使用JSON::XS等模块，从长远来看，你会好得多。

perl regex - 尝试将部分字符串捕获到新的var中

3 个答案: