我有以下文本文件和php代码,文本文件包含一些小变量,我希望能够从表单更新特定变量。
问题在于,当在提交时执行代码时,它会向文本文件添加额外的行,以防止从文本文档中正确读取变量。我在下面添加了文本文件,代码和结果。
文字档案
Title
Headline
Subheadline
extra 1
extra 2
php代码:
<?php
session_start();
// Get text file contents as array of lines
$filepath = '../path/file.txt';
$txt = file($filepath);
// Check post
if (isset($_POST["input"]) &&
isset($_POST["hidden"])) {
// Line to edit is hidden input
$line = $_POST['hidden'];
$update = $_POST['input'];
// Make the change to line in array
$txt[$line] = $update;
// Put the lines back together, and write back into text file
file_put_contents($filepath, implode("\n", $txt));
//success code
echo 'success';
} else {
echo 'error';
}
?>
修改后的文字文件:
Title edited
Headline
Subheadline
extra 1
extra 2
期望的结果:
Title edited
Headline
Subheadline
extra 1
extra 2
答案 0 :(得分:3)
感谢Cheery和Dagon有两个解决方案。
解决方案一
<?php
session_start();
// Get text file contents as array of lines
$filepath = '../path/file.txt';
$txt = file($filepath);
//check post
if (isset($_POST["input"]) &&
isset($_POST["hidden"])) {
$line = $_POST['hidden'];
$update = $_POST['input'] . "\n";
// Make the change to line in array
$txt[$line] = $update;
// Put the lines back together, and write back into txt file
file_put_contents($filepath, implode("", $txt));
//success code
echo 'success';
} else {
echo 'error';
}
?>
解决方案二
<?php
session_start();
// Get text file contents as array of lines
$filepath = '../path/file.txt';
$txt = file($filepath);
// Get file contents as string
$content = file_get_contents($filepath);
//check post
if (isset($_POST["input"]) &&
isset($_POST["hidden"])) {
$line = $_POST['hidden'];
$update = $_POST['input'] . "\n";
// Replace initial string (from $txt array) with $update in $content
$newcontent = str_replace($txt[$line], $update, $content);
file_put_contents($filepath, $newcontent);
//success code
echo 'success';
} else {
echo 'error';
}
?>