我有一个bash脚本，要求此人首先选择显示当前目录中文件的顺序。接下来，我让他们从使用select循环创建的列表中选择一个文件。在他们选择文件后，它会询问他们想要使用哪种类型的命令。我的问题是我想一次只向用户显示一定数量的文件。假设我想一次列出23个文件。我该怎么做？
抱歉，如果它是马虎的
ORDER=("name" "age" "size")
select OPT4 in "${ORDER[@]}"
do
if [[ $OPT4 == "name" ]]
then
ARRAY=( $( ls . ) )
# select OPT2 in "${ARRAY[@]}"
# do
# echo $OPT2
# done
fi
if [[ $OPT4 == "age" ]]
then
ARRAY=( $( ls -rt ) )
# select OPT2 in "${ARRAY[@]}"
# do
# echo $OPT2
# done
fi
if [[ $OPT4 == "size" ]]
then
ARRAY=( $( ls -S ) )
# select OPT2 in "${ARRAY[@]}"
# do
# echo $OPT2
# done
fi
echo $OPT4
#ARRAY=( $( ls -S ) )
select OPT2 in "${ARRAY[@]}"
do
OPTIONS=("author" "type" "copy" "ren" "move" "del" "copy!" "ren!" "move!" "help")
select OPT1 in "${OPTIONS[@]}"
do
if [[ $OPT1 == "copy!" || $OPT1 == "move!" || $OPT1 == "ren!" ]]
then
select OPT3 in "${ARRAY[@]}"
do
echo $OPT3
break
done
fi
if [[ $OPT1 == "copy" || $OPT == "move" || $OPT1 == "ren" ]]
then
echo -n "Enter a file destination: "
read OPT3
fi
case $OPT1 in
$AUTHOR)
echo "Last, First";;
$TYPE)
exist
file
order66;;
$COPY)
exist
file
order66;;
$RENAME)
# mv &>/dev/null $2 $3;;
exist
file
order66;;
$MOVE)
# mv &>/dev/null $2 $3;;
exist
file
order66;;
$DELETE)
# rm -f &>/dev/null $2;;
exist
file
order66;;
$FORCE_COPY)
exist
file
order67;;
$FORCE_MOVE)
exist
file
order67;;
$FORCE_RENAME)
exist
file
order67;;
$HELP)
echo -e $MESSAGE;;
*)
echo -e $MESSAGE;;
esac
exit
done
done
done
答案 0 :(得分：0)
您最好的解决方案是将文件列表读入一个数组，然后实现一个简单的寻呼机。然后，您可以使用c-style for loop来跟踪文件索引并根据循环索引的值进行操作。以下显示了寻呼机的实现。您要对索引执行的操作只是添加到read语句（例如：read -p "(#)Select File (f)orward (b)ack : " ans）并包含else来处理#）。我已经在寻呼机示例下面发布了文件名选择的附加代码。
每页显示的文件数由pg_size变量控制。根据需要调整。同样，您可以通过调整填充文件数组的find语句来控制是否递归读取文件：
#!/bin/bash
declare -i pg_size=4
file_array=( $(find "$1" -maxdepth 1 -type f) )
for ((i=0; i<${#file_array[@]}; i++)); do
echo " ${i}. ${file_array[$i]}"
if [ "$i" -gt 0 -a $(((i+1)%pg_size)) -eq 0 ]; then
read -p "(f)orward (b)ack : " ans
if [ "$ans" = 'b' ]; then
[ "$i" -gt "$((pg_size))" ] && ((i = i - (2*pg_size))) || ((i = i - pg_size))
fi
fi
done
输出示例：
$ ./lspager.sh tmp
0. tmp/File1950text.doc
1. tmp/vcs1dump
2. tmp/File2014text.xls
3. tmp/File307list.cvs
(f)orward (b)ack : b
0. tmp/File1950text.doc
1. tmp/vcs1dump
2. tmp/File2014text.xls
3. tmp/File307list.cvs
(f)orward (b)ack : f
4. tmp/vcsa1dump
5. tmp/File256name.txt
6. tmp/README.txt
7. tmp/dl
(f)orward (b)ack : b
0. tmp/File1950text.doc
1. tmp/vcs1dump
2. tmp/File2014text.xls
3. tmp/File307list.cvs
(f)orward (b)ack : f
4. tmp/vcsa1dump
5. tmp/File256name.txt
6. tmp/README.txt
7. tmp/dl
(f)orward (b)ack : f
8. tmp/File1949text.doc
9. tmp/vcsadump
10. tmp/vcsdump
11. tmp/helloworld.txt
(f)orward (b)ack : f
12. tmp/File1951text.dat
要实现文件名选择，只需添加到read并实施测试以验证范围内的数字答案并突破循环：
#!/bin/bash
declare -i pg_size=4
file_array=( $(find "$1" -maxdepth 1 -type f) )
for ((i=0; i<${#file_array[@]}; i++)); do
echo " ${i}. ${file_array[$i]}"
if [ "$i" -gt 0 -a $(((i+1)%pg_size)) -eq 0 ]; then
read -p "(#)Select file (f)orward (b)ack : " ans
if [ "$ans" = 'b' ]; then
[ "$i" -gt "$((pg_size))" ] && ((i = i - (2*pg_size))) || ((i = i - pg_size))
elif [[ "$ans" =~ [0-9] ]]; then # note character class, [[, and =~ are bash only
[ "$ans" -le "$i" ] && echo "You chose '$ans' - ${file_array[$ans]}" && break
fi
fi
done
<强>输出：
$ ./lspager.sh tmp
0. tmp/File1950text.doc
1. tmp/vcs1dump
2. tmp/File2014text.xls
3. tmp/File307list.cvs
(#)Select file (f)orward (b)ack : f
4. tmp/vcsa1dump
5. tmp/File256name.txt
6. tmp/README.txt
7. tmp/dl
(#)Select file (f)orward (b)ack : f
8. tmp/File1949text.doc
9. tmp/vcsadump
10. tmp/vcsdump
11. tmp/helloworld.txt
(#)Select file (f)orward (b)ack : b
4. tmp/vcsa1dump
5. tmp/File256name.txt
6. tmp/README.txt
7. tmp/dl
(#)Select file (f)orward (b)ack : 5
You chose '5' - tmp/File256name.txt