java - 使用SAX Parser进行XSD验证的java.security.AccessControlException

我在Google App Engine Web应用程序中编写了一个SAX解析器。在那里我尝试用xsd验证我的xml文件。但是当我的代码用来访问xsd时，我得到了一个访问控制异常。

java.security.AccessControlException: access denied (java.io.FilePermission \WEB-INF\ApplicationResponse.xsd read) at java.security.AccessControlContext.checkPermission(AccessControlContext.java:264) at java.security.AccessController.checkPermission(AccessController.java:427) at java.lang.SecurityManager.checkPermission(SecurityManager.java:532) at com.google.appengine.tools.development.DevAppServerFactory$CustomSecurityManager.checkPermission(DevAppServerFactory.java:166) at java.lang.SecurityManager.checkRead(SecurityManager.java:871) at java.io.FileInputStream.(FileInputStream.java:100) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.xsdToXMLInputSource(XMLSchemaLoader.java:830) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.processJAXPSchemaSource(XMLSchemaLoader.java:708) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadSchema(XMLSchemaLoader.java:554) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.findSchemaGrammar(XMLSchemaValidator.java:2459) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.handleStartElement(XMLSchemaValidator.java:1807) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.startElement(XMLSchemaValidator.java:705) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:330) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl$NSContentDispatcher.scanRootElementHook(XMLNSDocumentScannerImpl.java:779) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(XMLDocumentFragmentScannerImpl.java:1794) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:368) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:834) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:764) at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:148) at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1242) at sax.SAXLocalNameCount.parse(SAXLocalNameCount.java:220) at com.sms2mint.InterfaceServlet.doGet(InterfaceServlet.java:54)

请让我知道如何调试这个？我试图将xsd放在类，webcontent，/ WEB-INF中，但没有帮助。同样在appengine-web.xml中将其声明为资源文件，但无济于事。

使用SAX Parser进行XSD验证的java.security.AccessControlException

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