我正在尝试将测试移植到NUnit3并且收到System.ArgumentException:不支持'async void'方法,请改为使用'async Task'。
[Test]
public void InvalidUsername()
{
...
var exception = Assert.Throws<HttpResponseException>(async () => await client.LoginAsync("notarealuser@example.com", testpassword));
exception.HttpResponseMessage.StatusCode.ShouldEqual(HttpStatusCode.BadRequest); // according to http://tools.ietf.org/html/rfc6749#section-5.2
...
}
Assert.Throws似乎采用TestDelegate,定义为:
public delegate void TestDelegate();
因此ArgumentException。移植此代码的最佳方法是什么?
答案 0 :(得分:46)
这是由Nunit解决的。您现在可以使用Assert.ThrowsAsync&lt;&gt;()
https://github.com/nunit/nunit/issues/1190
示例:
Assert.ThrowsAsync<Exception>(() => YourAsyncMethod());
答案 1 :(得分:4)
我建议使用以下代码而不是Assert.ThrowsAsync
,因为这更具可读性:
// Option A
[Test]
public void YourAsyncMethod_Throws_YourException_A()
{
// Act
AsyncTestDelegate act = () => YourAsyncMethod();
// Assert
Assert.That(act, Throws.TypeOf<YourException>());
}
// Option B (local function)
[Test]
public void YourAsyncMethod_Throws_YourException_B()
{
// Act
Task Act() => YourAsyncMethod();
// Assert
Assert.That(Act, Throws.TypeOf<YourException>());
}
答案 2 :(得分:1)
为了确保抛出异常,如果您选择使用catch块,最好不要在catch块中断言。这样,您可以确保抛出了正确的异常类型,否则您将获得空引用或未捕获的异常异常。
HttpResponseException expectedException = null;
try
{
await client.LoginAsync("notarealuser@example.com", testpassword));
}
catch (HttpResponseException ex)
{
expectedException = ex;
}
Assert.AreEqual(HttpStatusCode.NoContent, expectedException.Response.BadRequest);
答案 3 :(得分:0)
我最终编写了一个反映NUnit功能的静态函数。在https://github.com/nunit/nunit/issues/464就此进行了一次完整的对话。
public static async Task<T> Throws<T>(Func<Task> code) where T : Exception
{
var actual = default(T);
try
{
await code();
Assert.Fail($"Expected exception of type: {typeof (T)}");
}
catch (T rex)
{
actual = rex;
}
catch (Exception ex)
{
Assert.Fail($"Expected exception of type: {typeof(T)} but was {ex.GetType()} instead");
}
return actual;
}
然后从我的测试我可以使用它,如
var ex = await CustomAsserts.Throws<HttpResponseException>(async () => await client.DoThings());
Assert.IsTrue(ex.Response.StatusCode == HttpStatusCode.BadRequest);
答案 4 :(得分:-3)
您可以尝试使用以下内容:
try
{
await client.LoginAsync("notarealuser@example.com", testpassword);
}
catch (Exception ex)
{
Assert.That(ex, Is.InstanceOf(typeof (HttpResponseException)));
}