我有两个html页面 - 一个用于登录,另一个用于接收人员详细信息。登录页面是第一页,当检查数据库的用户名和密码时,允许用户输入其详细信息。 SQL代码工作得很好,这只是我所拥有的映射的一个问题。我顺便使用Tomcat服务器。任何人都可以帮助或发现我做错了吗?
这是我登录和输入详细信息的java代码
public class Details extends HttpServlet {
private Connection con;
public void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
res.setContentType("text/html");
//return writer
PrintWriter out = res.getWriter();
String username = req.getParameter("username");
String password = request.getParameter("password");
out.close();
try {
login(username, password);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
res.sendRedirect("/redirect.html");
String name = request.getParameter("name");
String address = request.getParameter("address");
String age = request.getParameter("age");
out.println("<HTML><HEAD><TITLE>Personnel Details</TITLE></HEAD><BODY>");
out.println(name + address + age);
out.println("</BODY></HTML>");
System.out.println("Finished Processing");
}
out.close();
}
在我的web.xml文件中,我有:
<web-app>
<servlet>
<servlet-name>Details</servlet-name>
<servlet-class>Details</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Details</servlet-name>
<url-pattern>/Details</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>redirect</servlet-name>
<url-pattern>/redirect</url-pattern>
答案 0 :(得分:7)
你可以试试这个:
response.sendRedirect("redirect.html");
或
response.setStatus(response.SC_MOVED_TEMPORARILY);
response.setHeader("Location", "redirect.html");
替代方式,
ServletContext sc = getServletContext();
sc.getRequestDispatcher("/redirect.html").forward(request, response);
答案 1 :(得分:0)
重定向到HTML
RequestDispatcher ds = request.getRequestDispatcher("index.html");<br>
ds.include(request, response);
答案 2 :(得分:0)
您可以使用
1.response.sendRedirect("redirect.html")
或
2.String path= "/redirect";
RequestDispatcher dispatcher =servletContext().getRequestDispatcher(path);
dispatcher.forward(request,response);