Question

我需要过滤查询结果，以便其中一个选定的聚合字段满足特定条件。在这种情况下，让nvk.quality_id等于81或82. 81或81条件仅适用于我不计算其他字段的一个字段。此查询按预期工作：

SELECT 
    cams.name AS Campaign_Name,
    clk.type,
    COUNT(DISTINCT clk.eid) AS Dist_Eids_Sent,
    COUNT(DISTINCT nvk.eid) AS Dist_Leads
FROM bm_arc.clicks156 clk
INNER JOIN bm_queue.campaigns cams ON clk.camp = cams.id 
LEFT JOIN bm_emails.nvk156 nvk ON nvk.eid = clk.eid AND quality_id IN (81,82) # Hot, Warm
GROUP BY Campaign_Name, type

此处的结果如下所示：

Campaign Name | type | Dist_Eids_Sent | Dist_Leads
dogs          | 1    | 1000           | 100
cats          | 1    | 900            | 80

这些结果是正确的，符合我们的期望。 81和82是Dist_Leads类型的描述。我们希望结果中有热门或热门。

但是，而不是说AND quality_id IN (81,82) # Hot, Warm我想在选择器中使用这两个ID的英文含义。

要做到这一点，我必须加入查询 bm_config.classes cls ON nvk.quality_id = cls.id AND (cls.cid = 156 AND cls.name IN ('Hot', 'Warm'))

这看起来像：

SELECT 
    cams.name AS Campaign_Name,
    clk.type,
    COUNT(DISTINCT clk.eid) AS Dist_Eids_Sent,
    COUNT(DISTINCT nvk.eid) AS Dist_Leads
FROM bm_arc.clicks156 clk
INNER JOIN bm_queue.campaigns cams ON clk.camp = cams.id 
LEFT JOIN bm_emails.nvk156 nvk ON nvk.eid = clk.eid
LEFT JOIN bm_config.classes cls ON nvk.quality_id = cls.id AND cls.name IN ('Hot', 'Warm'))
GROUP BY Campaign_Name, type

但结果看起来像这样：

Campaign Name | type | Dist_Eids_Sent | Dist_Leads
dogs          | 1    | 1000           | 990
cats          | 1    | 900            | 850

然而，在Dist_Leads为Dist_Eids_Sent的约10％之前，它现在约为90％+

我不明白这里发生了什么。看起来附加连接正在连接到基表clk并改变结果

是否可以将我的LEFT JOIN编辑到nvk上，以便此连接仅适用于与cls.name相对应的记录＆＃34; hot＆＃34;或者＆＃34;温暖＆＃34;。 A＆＃34;嵌套连接＆＃34;如果你愿意的话。

它看起来像这样：

 LEFT JOIN bm_emails.nvk156 nvk ON nvk.eid = clk.eid AND
    bm_config.classes cls ON nvk.quality_id = cls.id AND
    (cls.cid = 156 AND cls.name IN ('Hot', 'Warm')

希望我要求的是有道理的。我基本上试图将所有过滤添加到一个左连接中，以免影响其余的查询结果。

Answer 1

如果那不太正确，请原谅我。我通常不会使用MySql！

SELECT 
    cams.name AS Campaign_Name,
    clk.type,
    COUNT(DISTINCT clk.eid) AS Dist_Eids_Sent,
    COUNT(DISTINCT nvk.eid) AS Dist_Leads
FROM bm_arc.clicks156 clk
INNER JOIN bm_queue.campaigns cams ON clk.camp = cams.id     
LEFT JOIN 
    ( SELECT
         eid 
         FROM bm_emails.nvk156
         INNER JOIN bm_config.classes cls ON nvk.quality_id = cls.id
         WHERE cls.name IN ('Hot', 'Warm')
    )  nvk ON nvk.eid = clk.eid
GROUP BY Campaign_Name, type

在一个连接中加入两个表

1 个答案: