如何REGEXP_REPLACE特殊字符

Question

我遇到以下正则表达式的问题

select REGEXP_REPLACE(declinereasondesc, '(.+)(£)(\d+)', '\1\3 (GBP)') as r from DECLINEREASON t

它与后续行

不匹配

Too expensive : By less than £100
Too expensive : By more than £200

预期结果

Too expensive : By less than 100 (GBP)
Too expensive : By more than 200 (GBP)

修改

非信徒的截图

Answer 1

我自己认为问题是£因为我确信每个人都怀疑

解决方案包含两个步骤，首先是获取符号代码，即使您将粘贴£复制到select ascii() from dual它也不会飞。您必须选择如下的符号才能获得正确的代码。

select ascii(substr(declinereasondesc, 30,1)) from DECLINEREASON t
where declinereasonid = 7;

在我的情况下，它给了49827

然后

select REGEXP_REPLACE(declinereasondesc, '(.+)('||chr(49827)||')(\d+)', '\1\3 (GBP)') from DECLINEREASON t;

然后才有效。