Question

我想基于MySql Value显示/隐藏元素

$(document).bind('DOMNodeInserted', '#composeHeaderTable0', function(event) {
    if ($('#data_parent_type0').val() == 'Leads') {
    $("#email_template0 option[value='151ddf5a-3fe8-84bd-50db-533545893c67']").hide();
    $("#email_template0 option[value='15a6040b-bbad-1a89-d62b-537de2b73832']").show();
}
    if ($('#data_parent_type0').val() == 'Contacts') {
    $("#email_template0 option[value='1b560788-07b2-0798-6b09-5335520bd9df']").hide();
    $("#email_template0 option[value='f15bf4b4-d174-f0d6-6f09-537c8d3e9693']").show();

}
    return false;
});

上面的脚本有效，但我需要显示基于Mysql调用的hide：我有部分php对应文件

<?php
    mysql_connect('mysql', 'admin', '123');
    mysql_select_db('mydb');
    $Leads0emailAddress0 = mysql_real_escape_string($_POST['Leads0emailAddress0']);
    $result = mysql_query('select id from email_templates where description = 'Customers' and deleted = 0;');
...............
?>

Answer 1

使用隐藏的表单元素，将其值设置为从mysql获取的结果。为该表单元素分配特定ID。从jQuery，使用ID引用该表单元素。这应该可以解决问题。

Answer 2

您的mysql脚本有错误

    $result = mysql_query('select id from email_templates where description = 'Customers' and deleted = 0;');

将其更改为

    $result = mysql_query(
              "SELECT id FROM 
                  email_templates 
                WHERE 
                  description = 'Customers' 
                AND deleted = 0"
             );

列出结果

$options = '';
while($row = mysql_fetch_assoc($result)) {
       $options .= '<option value="'.$row['id'].'">'.$row['id'].'</option>' . "\n";   
}

//display the options list in html where you want
<select id="email_template0">
   <?php echo $options; ?>
</select>

现在来自下拉列表更改的jQuery句柄事件

 $(function() {
 $("#email_template0").change(function() {
    alert( $('option:selected', this).val() );
    //do your hide and select here 
    });
 });

基于mysql选择的Jquery show / hide元素

2 个答案: