Question

我有以下代码删除“refs / changes / digit”但是没有得到预期的输出，我有如下所示的curent输出，任何人都可以提供输入如何解决这个问题？

source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
output = ' '.join(line.split('/', 3)[-1] for line in source.splitlines())
print output


CURRENT OUTPUT:-

1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2

expected output

1025744/3 1025962/5 913745/2

Answer 1

拆分空格然后拆分前三个"/"并提取最后一个元素。

source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
print(" ".join([ele.split("/",3)[-1] for ele in source.split()]))
1025744/3 1025962/5 913745/2

一些时间：

In [3]: import re

In [4]: timeit " ".join([ele.split("/",3)[-1] for ele in source.split()])
100000 loops, best of 3: 1.83 µs per loop

In [5]: timeit p.findall(source)

100000 loops, best of 3: 2.84 µs per loop

Answer 2

另一种方法是使用正则表达式：

import re
p = re.compile(r'(\d{6,7}/\d{1})')
source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
print p.findall(source)

请注意，我在斜杠前明确定义了6或7个字符的数字（您可以根据需要调整正则表达式）。

如何根据空间而不是新线进行拆分？

2 个答案: