private static String REGEX_ANY_MONTH = "January|Jan|February|Feb|March|Mar|April|Apr|May|June|Jun|"
+ "July|Jul|August|Aug|September|Sep|October|Oct|November|Nov|December|Dec";
private static String REGEX_ANY_YEAR = "[0-9]{4}";
private static String REGEX_ANY_DATE = "[0-9]{1,2}";
private String getFormat(String date) {
if (date.matches(REGEX_ANY_MONTH + " " + REGEX_ANY_DATE + "," + " " + REGEX_ANY_YEAR)) {
return "{MONTH} {DAY}, {YEAR}";
} else if (date.matches(REGEX_ANY_MONTH + " " + REGEX_ANY_YEAR)){
return "{MONTH} {YEAR}";
}
return null;
}
@Test
public void testGetFormatDateString() throws Exception{
String format = null;
String test = null;
test = "March 2012";
format = Whitebox.<String> invokeMethod(obj, "getFormat", test);
Assert.assertEquals("{MONTH} {YEAR}", format);
test = "March 10, 2012";
format = Whitebox.<String> invokeMethod(obj, "getFormat", test);
Assert.assertEquals("{MONTH} {DATE}, {YEAR}", format);
}
这两个断言对我来说都是失败的。我错过了什么?
答案 0 :(得分:3)
您需要将月份名称的管道列表包装在括号中,以便匹配。
private static String REGEX_ANY_MONTH = "(January|Jan|February|Feb|March|Mar|April|Apr|May|June|Jun|"
+ "July|Jul|August|Aug|September|Sep|October|Oct|November|Nov|December|Dec)";
否则'或'条件将超过月份。