Question

创建一个查询以显示员工总数，以及总数中的员工数量在2005年，2006年，2007年和2008年聘用。创建适当的列标题。

到目前为止，我已设法做到这一点：

SELECT COUNT(DISTINCT employee_id) AS "Total",
   (CASE WHEN hire_date BETWEEN '01-01-2005' AND '31-12-2005' THEN '2005'
       WHEN hire_date BETWEEN  '01-01-2006' AND '31-12-2006' THEN '2006'
       WHEN hire_date BETWEEN  '01-01-2007' AND '31-12-2007' THEN '2007'
       WHEN hire_date BETWEEN  '01-01-2008' AND '31-12-2008' THEN '2008'
       ELSE 'Out of Range'
       END ) AS "Years"
FROM   employees
WHERE  hire_date BETWEEN '31-12-2005' AND '01-01-2008'
GROUP BY hire_date;

但输出并不是应有的。由于我的声誉很低，无法上传图片，以确切了解我的意思:)。无论如何，有什么建议吗？

Answer 1

您应该使用这样的格式yyyy-MM-dd

SELECT COUNT(DISTINCT employee_id) AS "Total",
SUM( CASE WHEN hire_date BETWEEN '2005-01-01' AND '2005-12-31' THEN 1 else 0 end) as   
'2005', 
SUM( CASE WHEN hire_date BETWEEN '2006-01-01' AND '2006-12-31' THEN 1 else 0 end) as 
'2006',
SUM( CASE WHEN hire_date BETWEEN '2007-01-01' AND '2007-12-31' THEN 1 else 0 end) as 
'2007',
SUM( CASE WHEN hire_date BETWEEN '2008-01-01' AND '2008-12-31' THEN 1 else 0 end) as 
'2008',
SUM( CASE WHEN hire_date < '2005-01-01' OR  hire_date > '31-12-2008' 
THEN 1 else 0 end) as 
"Out of Range"
FROM   employees

Answer 2

您可以将查询更改为

SELECT COUNT(employee_id) AS "Total",
SUM(case when hire_date BETWEEN '01-01-2005' AND '31-12-2005' THEN 1 else 0 end) as '2005',
SUM(case WHEN hire_date BETWEEN  '01-01-2006' AND '31-12-2006' THEN 1 else 0 end) as '2006',
SUM(case WHEN hire_date BETWEEN  '01-01-2008' AND '31-12-2008' THEN 1 else 0 end) as '2008',
SUM(case WHEN hire_date BETWEEN  '01-01-2007' AND '31-12-2007' THEN 1 else 0 end) as '2007'
FROM   employees
GROUP BY hire_date;

SQL-Oracle：解决基本问题的困难

2 个答案: