当Oracle SQL具有不同的值时，它会获取id

Question

+----------+---------------------+-------+
| ID       | date_value          | value |
+----------+---------------------+-------+
| 1        | 2011-04-20 21:03:05 | 150   |
| 1        | 2011-04-20 21:03:04 | 150   |
| 2        | 2011-04-20 21:03:03 | 20    |
| 2        | 2011-04-20 21:02:09 | 130   |
| 2        | 2011-04-20 21:02:08 | 130   |
| 3        | 2011-04-20 21:02:07 | 20    |
| ...      | ...                 | ...   |
+----------+---------------------+-------+

使用此表，如何使用select来查找超过100的值超过2的ID？

Answer 1

SELECT ID, count(*) from mytable
WHERE value > 100
GROUP BY ID
HAVING count(*) >2

Answer 2

您可以执行以下操作

select id,count(value)
from table1
where value > 100
having count(value) > 2
group by ID;

Answer 3

您可以使用此SQL语句：

SELECT id, count(1)
FROM   mytable
WHERE  value > 100
GROUP BY id
HAVING count(1) > 2;