如何从tsql中删除数据和组中的最后一个数字,
查询
select browser from Table1 group by browser
结果
Chrome11
Chrome28
Chrome30
Chrome31
Chrome32
Chrome33
Firefox12
Firefox22
Firefox30
Firefox32
Firefox33
IE10
IE7
IE8
IE9
IEMobile
IEMobile10
InternetExplorer11
Mozilla
Opera9
Safari
Safari5
Safari6
所需格式
Chrome
Firefox
IE
Safari
InternetExplorer
Mozilla
IEMobile
注意:我们不会使用
的客户端浏览器答案 0 :(得分:1)
这将为你工作..
select distinct browser from (
select REPLACE (REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE
(browser, '0', ''),'1', ''),'2', ''),'3', ''),'4', ''),'5', ''),
'6', ''),'7', ''),'8', ''),'9', '') as browser
from TestTable group by browser) temp
答案 1 :(得分:0)
您可以使用嵌套的REPLACE(),它最多可达32级:
DECLARE @mystring NVARCHAR(30)
SET @mystring = 'TEST76'
select REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE (@mystring, '0', ''),
'1', ''),
'2', ''),
'3', ''),
'4', ''),
'5', ''),
'6', ''),
'7', ''),
'8', ''),
'9', '')
结果:TEST
希望这有帮助。
答案 2 :(得分:0)
WITH ExampleCte(Browser) AS (
SELECT
'Chrome11' UNION ALL SELECT
'Chrome28' UNION ALL SELECT
'Chrome30' UNION ALL SELECT
'Chrome31' UNION ALL SELECT
'Chrome32' UNION ALL SELECT
'Chrome33' UNION ALL SELECT
'Firefox12' UNION ALL SELECT
'Firefox22' UNION ALL SELECT
'Firefox30' UNION ALL SELECT
'Firefox32' UNION ALL SELECT
'Firefox33' UNION ALL SELECT
'IE10' UNION ALL SELECT
'IE7' UNION ALL SELECT
'IE8' UNION ALL SELECT
'IE9' UNION ALL SELECT
'IEMobile' UNION ALL SELECT
'IEMobile10' UNION ALL SELECT
'InternetExplorer11' UNION ALL SELECT
'Mozilla' UNION ALL SELECT
'Opera9' UNION ALL SELECT
'Safari' UNION ALL SELECT
'Safari5' UNION ALL SELECT
'Safari6'
)
SELECT
Browser,
Left(Browser, Len(Browser) - PatIndex('%[^0-9]%', Reverse(Browser)) + 1) AS BrowserWithoutNumber
FROM
ExampleCte
答案 3 :(得分:0)
你可以这样做:
测试数据:
DECLARE @tbl TABLE(browser VARCHAR(100))
INSERT INTO @tbl
VALUES
('Chrome11'),('Chrome28'),('Chrome30'),
('Chrome31'),('Chrome32'),('Chrome33'),
('Firefox12'),('Firefox22'),('Firefox30'),
('Firefox32'),('Firefox33'),('IE10'),
('IE7'),('IE8'),('IE9'),('IEMobile'),
('IEMobile10'),('InternetExplorer11'),('Mozilla'),
('Opera9'),('Safari'),('Safari5'),('Safari6')
然后是这样的查询:
;WITH CTE
AS
(
SELECT
(
CASE
WHEN PATINDEX('%[0-9.-]%', browser) = 0
THEN browser
ELSE SUBSTRING(browser,0,PATINDEX('%[0-9.-]%', browser))
END
) AS browser
FROM
@tbl AS tbl
)
SELECT
*
FROM
CTE
GROUP BY
CTE.browser
这会得到这样的输出:
Chrome
Firefox
IE
IEMobile
InternetExplorer
Mozilla
Opera
Safari
参考:
答案 4 :(得分:0)
创建一个功能:
Create Function fnStrFromAlphaNum(@str varchar(100))
returns varchar(100)
as
begin
if patindex('%[0-9]%',@str)>0
set @str = SUBSTRING(@str,1,patindex('%[0-9]%',@str)-1)
return @str
end
在您的查询中调用此函数:
select distinct fnStrFromAlphaNum(browser)
from table1
答案 5 :(得分:0)
你可以这样做:
WITH cte AS
(SELECT rtrim(
substring(
browser,
1,
PATINDEX('%[0-9]%', browser) -1
)
) as browser
FROM table)
SELECT cte.browser FROM cte
GROUP BY cte.browser