Question

我有一个使用HtmlUnit库的java应用程序，从xml页面获取源代码时遇到问题。我得到的只是一个＆＃34; ClassCastException＆＃34;错误。

我正在使用最新的HtmlUnit 2.15 API库。

 public static void main(String[] args) {
    WebClient webClient = new WebClient(BrowserVersion.CHROME);
    webClient = new WebClient(BrowserVersion.CHROME);
    webClient.getOptions().setJavaScriptEnabled(true);
    webClient.getOptions().setActiveXNative(false);
    webClient.getOptions().setAppletEnabled(false);
    webClient.getOptions().setCssEnabled(true);
    webClient.getOptions().setPopupBlockerEnabled(true);
    webClient.getOptions().setPrintContentOnFailingStatusCode(false);
    webClient.getOptions().setThrowExceptionOnFailingStatusCode(false);
    webClient.getOptions().setThrowExceptionOnScriptError(true);
    webClient.getOptions().setTimeout(100000);
    webClient.getOptions().setThrowExceptionOnScriptError(false);
    webClient.getOptions().setDoNotTrackEnabled(false);
    //webClient.getOptions().setProxyConfig(new ProxyConfig("10.0.0.1", 8080));
    try{    
        HtmlPage page = webClient.getPage("http://www.w3schools.com/xml/note.xml");
        // TODO, add your application code
        System.out.println(page.asXml());

    } catch (Exception e) {
        System.out.println("An error occurs when getting the page: "+e);
    }
}

关于如何通过htmlunit库检索xml文件并将其保存到文件的任何想法？

Answer 1

我最终想通了。

转而我们首先需要导入com.gargoylesoftware.htmlunit.xml.XmlPage;

然后，您可以声明XmlPage对象，从而避免出现ClassCastException问题。

所以对于那些也是HtmlUnit

的新手，我的代码看起来像这样

public static void main(String[] args) {

    WebClient webClient = new WebClient(BrowserVersion.CHROME);

    XmlPage page = null;

    webClient = new WebClient(BrowserVersion.CHROME);
    webClient.getOptions().setJavaScriptEnabled(true);
    webClient.getOptions().setActiveXNative(false);
    webClient.getOptions().setAppletEnabled(false);
    webClient.getOptions().setCssEnabled(true);
    webClient.getOptions().setPopupBlockerEnabled(true);
    webClient.getOptions().setPrintContentOnFailingStatusCode(false);
    webClient.getOptions().setThrowExceptionOnFailingStatusCode(false);
    webClient.getOptions().setThrowExceptionOnScriptError(true);
    webClient.getOptions().setTimeout(100000);
    webClient.getOptions().setThrowExceptionOnScriptError(false);
    webClient.getOptions().setDoNotTrackEnabled(false);
    //webClient.getOptions().setProxyConfig(new ProxyConfig("10.0.0.1", 8080));

    try {

        //go to url
        page = webClient.getPage("http://www.w3schools.com/xml/note.xml");
        System.out.println(xpage.asXml());

        //just for test save to file to see results
        File file = new File("result.html");
        FileOutputStream fos = new FileOutputStream(file);

        fos.write(xpage.asXml().getBytes());
        fos.close();
        //end test

    } catch (Exception e) {
        System.out.println("An error occurs when getting the page: "+e);

    }

}

Java htmlUnit获取xml页面ClassCastException问题

1 个答案: