Question

这里的测验类型我想在1个文本框中的任何一个中删除任何1个选项（a），（b），（c），（d）............. .................................................. .................................................. .................................................. .................................................. .................................................. .... jsfiddle是http://jsfiddle.net/5DCZw/962/

  <div class="ans_set1">
     <input type="text" maxlength="10" class="ans_set1_1" />
    <br><input type="text"  maxlength="0" class="ans_set1_2" />
    <br><input type="text" maxlength="0" class="ans_set1_3" />
   <br><input type="text" maxlength="0" class="ans_set1_4" />
 </div>



<div class="abcd">
<div class="a" id="draggable"><b>(a)</b>
</div>
<div class="b" id="draggable"><b>(b)</b>
</div>
<div class="c" id="draggable"><b>(c)</b>
</div>
<div class="d" id="draggable"><b>(d)</b>
</div>
</div>

$(document).ready(function () {
$(function () {
    $(".a,.b,.c,.d").draggable({
        revert: true,
        helper: 'clone',
        start: function (event, ui) {
            $(this).fadeTo('fast', 0.5);
        },
        stop: function (event, ui) {
            $(this).fadeTo(0, 1);
        }
    });
    $(".ans_set1_1,.ans_set1_2,.ans_set1_3,.ans_set1_4").droppable({
        accept: ".a,.b,.c,.d",
        drop: function (event, ui) {

         }
      });
   });
 } );



         jsfiddle is http://jsfiddle.net/5DCZw/962/

Answer 1

http://jsfiddle.net/5DCZw/963/

$(document).ready(function () {
    $(function () {
        $(".a,.b,.c,.d").draggable({
            revert: true,
            helper: 'clone',
            start: function (event, ui) {
                $(this).fadeTo('fast', 0.5);
            },
            stop: function (event, ui) {
                $(this).fadeTo(0, 1);
            }
        });
        $(".ans_set1_1,.ans_set1_2,.ans_set1_3,.ans_set1_4").droppable({
            accept: ".a,.b,.c,.d",
            drop: function (event, ui) {
                  var $answer=ui.draggable;
                  var $input=$(event.target);

                  var val=$answer.text()

                  $input.val(val);
            }
        });
    });
});

拖放不能按预期正常工作

1 个答案: