我已经将一堆图像上传到Amazon S3,现在想要为它们添加一个Cache-Control标头。
是否可以在不下载整个图像的情况下更新标题?如果是这样,怎么样?
答案 0 :(得分:34)
这是测试版功能,但您可以在copy an object时指定新的元数据。为副本指定相同的源和目标,这样只会更新对象上的元数据。
PUT /myObject HTTP/1.1
Host: mybucket.s3.amazonaws.com
x-amz-copy-source: /mybucket/myObject
x-amz-metadata-directive: REPLACE
x-amz-meta-myKey: newValue
答案 1 :(得分:10)
这是测试版,可通过执行put命令并将对象复制为documented here来实现。它也可以在他们的SDK中找到。例如,使用C#:
var s3Client = new AmazonS3Client("publicKey", "privateKey");
var copyRequest = new CopyObjectRequest()
.WithDirective(S3MetadataDirective.REPLACE)
.WithSourceBucket("bucketName")
.WithSourceKey("fileName")
.WithDestinationBucket("bucketName")
.WithDestinationKey("fileName)
.WithMetaData(new NameValueCollection { { "x-amz-meta-yourKey", "your-value }, { "x-amz-your-otherKey", "your-value" } });
var copyResponse = s3Client.CopyObject(copyRequest);
答案 2 :(得分:7)
这是您使用适用于PHP 2的AWS开发工具包的方法:
<?php
require 'vendor/autoload.php';
use Aws\Common\Aws;
use Aws\S3\Enum\CannedAcl;
use Aws\S3\Exception\S3Exception;
const MONTH = 2592000;
// Instantiate an S3 client
$s3 = Aws::factory('config.php')->get('s3');
// Settings
$bucketName = 'example.com';
$objectKey = 'image.jpg';
$maxAge = MONTH;
$contentType = 'image/jpeg';
try {
$o = $s3->copyObject(array(
'Bucket' => $bucketName,
'Key' => $objectKey,
'CopySource' => $bucketName . '/'. $objectKey,
'MetadataDirective' => 'REPLACE',
'ACL' => CannedAcl::PUBLIC_READ,
'command.headers' => array(
'Cache-Control' => 'public,max-age=' . $maxAge,
'Content-Type' => $contentType
)
));
// print_r($o->ETag);
} catch (Exception $e) {
echo $objectKey . ': ' . $e->getMessage() . PHP_EOL;
}
?>
答案 3 :(得分:2)
使用amazon aws-sdk,执行带有额外标头的copy_object似乎可以为现有S3对象设置缓存控制标头。
===================== X ========================= ======================
<?php
error_reporting(-1);
require_once 'sdk.class.php';
// UPLOAD FILES TO S3
// Instantiate the AmazonS3 class
$options = array("key" => "aws-key" , "secret" => "aws-secret") ;
$s3 = new AmazonS3($options);
$bucket = "bucket.3mik.com" ;
$exists = $s3->if_bucket_exists($bucket);
if(!$exists) {
trigger_error("S3 bucket does not exists \n" , E_USER_ERROR);
}
$name = "cows-and-aliens.jpg" ;
echo " change headers for $name \n" ;
$source = array("bucket" => $bucket, "filename" => $name);
$dest = array("bucket" => $bucket, "filename" => $name);
//caching headers
$offset = 3600*24*365;
$expiresOn = gmdate('D, d M Y H:i:s \G\M\T', time() + $offset);
$headers = array('Expires' => $expiresOn, 'Cache-Control' => 'public, max-age=31536000');
$meta = array('acl' => AmazonS3::ACL_PUBLIC, 'headers' => $headers);
$response = $s3->copy_object($source,$dest,$meta);
if($response->isOk()){
printf("copy object done \n" );
}else {
printf("Error in copy object \n" );
}
?>
======================= X ======================= =========================
答案 4 :(得分:1)
在Java中,试试这个
S3Object s3Object = amazonS3Client.getObject(bucketName, fileKey);
ObjectMetadata metadata = s3Object.getObjectMetadata();
Map customMetaData = new HashMap();
customMetaData.put("yourKey", "updateValue");
customMetaData.put("otherKey", "newValue");
metadata.setUserMetadata(customMetaData);
amazonS3Client.putObject(new PutObjectRequest(bucketName, fileId, s3Object.getObjectContent(), metadata));
您也可以尝试复制对象。复制对象时,元数据不会复制。 您必须获取原始元数据并设置为复制请求。 建议使用此方法插入或更新Amazon S3对象的元数据
ObjectMetadata metadata = amazonS3Client.getObjectMetadata(bucketName, fileKey);
ObjectMetadata metadataCopy = new ObjectMetadata();
metadataCopy.addUserMetadata("yourKey", "updateValue");
metadataCopy.addUserMetadata("otherKey", "newValue");
metadataCopy.addUserMetadata("existingKey", metadata.getUserMetaDataOf("existingValue"));
CopyObjectRequest request = new CopyObjectRequest(bucketName, fileKey, bucketName, fileKey)
.withSourceBucketName(bucketName)
.withSourceKey(fileKey)
.withNewObjectMetadata(metadataCopy);
amazonS3Client.copyObject(request);