Question

应用程序崩溃并显示此错误消息（Exc_bad_access（code = 1，address = 0x208））。应用程序停止并显示错误的行是最后一行（var result）。这是代码：

// 1. Get the name and the path for DB
self.DBName = @"PhonePager.db";
NSArray * documentsPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString * documentDir = [documentsPaths objectAtIndex:0];
self.DBPath = [documentDir stringByAppendingPathComponent:self.DBName];
const char * dbpath = [self.DBPath UTF8String];

// 2. Open database
if (sqlite3_open(dbpath, &contactDB) == SQLITE_OK)
{

    // 3. Create requests ( fill the table messages received )
     NSString * statementGetDataFromDB = [NSString stringWithFormat:@"SELECT id_message, date, time, ack_required, auto_ack_sent, message, titre, idfrom FROM messages m WHERE NOT EXISTS(SELECT id_message FROM responses r WHERE r.id_message = m.id_message) ORDER BY date DESC, time DESC"];

    const char * sql_stmt_getDataFromDB  = [statementGetDataFromDB UTF8String];

    // 4. Execute request
    sqlite3_stmt * sqlStatement;
    int result = sqlite3_prepare_v2(contactDB, sql_stmt_getDataFromDB, -1, &sqlStatement, nil);

你有什么建议吗？提前致谢

Answer 1

据我所知，你正在尝试向c函数发送一个目标c指针（nil）。在这一行;

int result = sqlite3_prepare_v2(contactDB, sql_stmt_getDataFromDB, -1, &sqlStatement, nil);

试试这个;

int result = sqlite3_prepare_v2(contactDB, sql_stmt_getDataFromDB, -1, &sqlStatement, NULL);

Exc_bad_access（代码= 1，地址= 0x208）

1 个答案: