Question

以下代码有效。 - 它在预定位置500米范围内的地图上显示“商店”。 - 它在地图上显示带有商店详细信息的标记。 - 它确实显示了地图列表，但只显示地名而不是详细信息（我想了解详情）。

如果我想输出上面的HTML / Javascript列表而不是显示地图，怎么会找到如何做到这一点？

Google Places API，重点介绍如何输出到地图，但我不想仅在地图上输出商店信息。如果您有任何线索，请告诉我。我只需要建议。

<!DOCTYPE html>
<html>
  <head>
    <title>Place searches</title>
    <meta name="viewport" content="initial-scale=1.0, user-scalable=no">
    <meta charset="utf-8">
    <style>
      html, body, #map-canvas {
        height: 100%;
        margin: 0px;
        padding: 0px
      }
    </style>
  <script src="https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=places"></script>
    <script>
var map, placesList;
var infowindow;
var service; //declare globally


function initialize() {
  var pyrmont = new google.maps.LatLng(40.062664, -83.069101);

  map = new google.maps.Map(document.getElementById('map-canvas'), {
    center: pyrmont,
    zoom: 15
  });

  var request = {
    location: pyrmont,
    radius: 500,
    types: ['store']
  };
  infowindow = new google.maps.InfoWindow();
   placesList = document.getElementById('places');
 service = new google.maps.places.PlacesService(map);
  service.nearbySearch(request, callback);
service.getDetails(request, callback);

}

function callback(results, status) {
  if (status == google.maps.places.PlacesServiceStatus.OK) {
    for (var i = 0; i < results.length; i++) {
      createMarker(results[i]);
    }
  }
}

function createMarker(place) {
  var placeLoc = place.geometry.location;
  var marker = new google.maps.Marker({
  map: map,
  position: place.geometry.location
 });

var request = { placeId: place.place_id };
service.getDetails(request, function(details, status) {
  google.maps.event.addListener(marker, 'click', function() {
    infowindow.setContent(details.name + "<br />" + details.formatted_address +"<br />" + details.website + "<br />" + details.rating + "<br />" + details.formatted_phone_number);
    infowindow.open(map, this);
   });
 });
 placesList.innerHTML += '<li>' + place.name  + '</li>';
}



google.maps.event.addDomListener(window, 'load', initialize);

    </script>
    <style>
      #results {
        font-family: Arial, Helvetica, sans-serif;
        position: absolute;
        right: 5px;
        top: 50%;
        margin-top: -195px;
        height: 380px;
        width: 500px;
        padding: 5px;
        z-index: 5;
        border: 1px solid #999;
        background: #fff;
      }
      h2 {
        font-size: 22px;
        margin: 0 0 5px 0;
      }
      ul {
        list-style-type: none;
        padding: 0;
        margin: 0;
        height: 321px;
        width: 500px;
        overflow-y: scroll;
      }
      li {
        background-color: #f1f1f1;
        padding: 10px;
        text-overflow: ellipsis;
        white-space: nowrap;
        overflow: hidden;
      }
      li:nth-child(odd) {
        background-color: #fcfcfc;
      }
      #more {
        width: 100%;
        margin: 5px 0 0 0;
      }
    </style>
  </head>
  <body>
    <div id="map-canvas"></div>
     <div id="results">
      <h2>Results</h2>
      <ul id="places"></ul>
      <button id="more">More results</button>
    </div>
  </body>
</html>

Answer 1

我看到你已经填写了一个html的地方列表，为什么还不够？

关于地方详细信息，我尝试在相关标记上设置监听器，而不是尝试获取每个检索到的地方的详细信息。如果有人点击该标记，那么我将启动详细信息请求并相应地打开信息窗

function createMarker(place) {

    var placeLoc = place.geometry.location;
    var marker = new google.maps.Marker({
      map: map,
      position: place.geometry.location
    });
    var request = { placeId: place.place_id };

    google.maps.event.addListener(marker, 'click', function() {
      service.getDetails(request, function(details, status) {
        console.log(details,status);
        infowindow.setContent(details.name + "<br />" + details.formatted_address +"<br />" + details.website + "<br />" + details.rating + "<br />" + details.formatted_phone_number);
        infowindow.open(map, marker);
      });
   });

  placesList.innerHTML += '<li>' + place.name  + '</li>';
}

反过来会导致“OVER QUERY LIMIT”错误，因为你将同时向getDetails发出500个请求。

更新：here's a brief example，使用jQuery检测html列表上的点击并触发getDetails请求。

Google商家信息HTML / Javascript列表

1 个答案: