Django CMS多级下拉菜单

时间:2014-11-17 15:11:55

标签: recursion menu parent-child django-cms tree-structure

我是Django CMS的新手,我尽我所能避免询问,但这个让我发疯。 我创建了一个带有Topic和Category模型的Wiki应用程序。我将它连接到CMS上的网站并将其添加到我的菜单中。现在我希望能够显示所有顶级类别,他们的子类别&主题,以及这些主题的子类别,等等,在我的菜单上。

Menu/Navigation should look like this:

Wiki
    Category1
        Category1.1
            Topic
        Category1.2
        Topic
    Category2
        Topic
    Category3
        ...

Right now i can only show the Top categories:

Wiki
    Category1
    Category2
    Category3

我已经创建了一个menu.py来获取我的Wiki上的自定义子菜单(您在上面看到的那个):

menu.py

class WikiSubMenu(CMSAttachMenu):
    name = _("Wiki Sub-Menu")

    def get_nodes(self, request):
        nodes = []
        categories = Category.objects.filter(parent_id__isnull=True)

        for c in categories:
            node = NavigationNode(
                mark_safe(c.name),
                c.get_absolute_url(),
                c.id,

            )

            nodes.append(node)

        return nodes

menu_pool.register_menu(WikiSubMenu)

我的分类模型:

class Category(models.Model):
    ''' Category model. '''
    name = models.CharField(max_length=100)
    slug = models.SlugField(unique=True)
    description = models.TextField(blank=True)
    parent = models.ForeignKey(
        'self',
        null=True,
        blank=True,
        related_name='children'
    )
    sort = models.IntegerField(default=0)

    class Meta:
        ordering = ['sort', 'name']

    def __unicode__(self):
        return self.name

    @models.permalink
    def get_absolute_url(self):
        return ('topics:categories_category_detail', (), {'slug': self.slug})

    def get_all_children(self):
        return Category.objects.filter(parent=self)

现在,是否可以为包含Childs的所有类别及其Childs及其Childs创建Sub-SubMenu,等等?

感谢您的帮助&抱歉英文不好

- 编辑: -

我刚发现:

docs.django-cms.org/en/3.0.6/extending_cms/app_integration.html#integration-modifiers

(删除直接链接添加2个新链接,对不起)

我认为这就是我正在寻找的,我有点失明,我没有找到它。如果问题解决了,我会尝试并发布答案。

- 编辑(再次): -

改编者对我没有用,但我得到了更多的东西, 我再次阅读Docs,发现我可以给NavigationNodes一个可选的attr dictonary,我用parent = c填充所有类别,就这样我有我需要的数据,然后我发现真的很好bootstrap dropdown menu,这确实是我想要的。所以我的代码到现在为止看起来像这样:

menu.py

class TopicsSubMenu(CMSAttachMenu):
    name = _("Wiki Sub-Menu")

    def get_nodes(self, request):
        nodes = []
        categories = Category.objects.filter(parent_id__isnull=True)

        for c in categories:
            node = NavigationNode(
                mark_safe(c.name),
                c.get_absolute_url(),
                c.pk,
                attr=dict(
                    subcategories=Category.objects.filter(parent=c),),
            )

            nodes.append(node)
        return nodes

我的模板:

menu.html

{% for child in children %}
    <li>
        {% if child.children %}

            <a class="dropdown-toggle" data-toggle="dropdown" href="#">
                {{ child.get_menu_title }}
                <span class="caret">
                </span>
            </a>
            <ul class="dropdown-menu multi-level" role="menu" aria-labelledby="dropdownMenu">
                {% for child in child.children %}
                    {% if child.attr.subcategories.count %}
                        <li class="dropdown-submenu">
                            <a tabindex="-1" href="#">{{ child.get_menu_title }}</a>
                            <ul class="dropdown-menu">
                                {% for subcategory in child.attr.subcategories %}
                                <li>
                                    <a tabindex="-1" href="{{ subcategory.get_absolute_url }}">{{ subcategory }}</a>
                                </li>
                                {% endfor %}
                            </ul>


                        </li>
                    {% else %}
                    <li><a href="{{child.get_absolute_url}}">{{ child.get_menu_title }}</li></a>
                    {% endif %}
                {% endfor %}

            </ul>
        {% else %}
            <a href="{{ child.get_absolute_url }}">
                <span>
                    {{ child.get_menu_title }}
                </span>
            </a>
        {% endif %}
    </li>

    {% if class and forloop.last and not forloop.parentloop %}
    {% endif %}


{% endfor %}

我的下一步是写整个&#34; for&#34;从方法中的模板循环,使用while循环或其他东西递归,并将结果发布为Answer。

我希望我能用这些东西帮助别人:)

1 个答案:

答案 0 :(得分:5)

WOHO!我终于做到了!

base.html文件

<div class="navbar-collapse collapse">
    <ul class="nav navbar-nav">
        {% show_menu 0 100 100 100 "menu.html" %}
    </ul>
</div>

menu.html:

{% for child in children %}
    <li class="child{% if child.selected %} selected{% endif %}{% if child.ancestor %} ancestor{% endif %}{% if child.sibling %} sibling{% endif %}{% if child.descendant %} descendant{% endif %}{% if child.children %} dropdown{% endif %}">

        <a {% if child.children %}class="dropdown-toggle" data-toggle="dropdown"{% endif %} href="{{ child.attr.redirect_url|default:child.get_absolute_url }}">
            <span>{{ child.get_menu_title }}</span>{% if child.children|length %}<span class="caret"></span>{% endif %}
        </a>

        {% if child.children %}
            <ul class="dropdown-menu multi-level" role="menu" aria-labelledby="dropdownMenu">
                {% show_menu from_level to_level extra_inactive extra_active "dropdownmenu.html" "" "" child %}
            </ul>
        {% endif %}

    </li>
    {% if class and forloop.last and not forloop.parentloop %}{% endif %}

{% endfor %}

和我的dropdownmenu.html: (递归的东西从这里开始)

{% load i18n menu_tags cache mptt_tags %}
{% for child in children %}
    <li {% if child.children %}class="dropdown-submenu"{% else %} {% endif %}>
        <a tabindex="-1" href="{{ child.attr.redirect_url|default:child.get_absolute_url }}">{{ child.get_menu_title }}</a>
        {% if child.children %}
            <ul class="dropdown-menu">
                {% show_menu from_level to_level extra_inactive extra_active "dropdownmenu.html" "" "" child %}
            </ul>
        {% endif %}

    </li>
{% endfor %}

最重要的是menu.py:

class TopicsSubMenu(CMSAttachMenu):
    name = _("Wiki Sub-Menu")

    def get_nodes(self, request):
        nodes = []
        categories = Category.objects.all()

        for c in categories:
            node = NavigationNode(
                mark_safe(c.name),
                c.get_absolute_url(),
                c.pk
            )
            if c.parent:
                node.parent_id = c.parent_id
            nodes.append(node)

        topics = Topic.objects.all().exclude(category__isnull=True)
        for t in topics:
            node = NavigationNode(
                mark_safe(t.title),
                t.get_absolute_url(),
                t.pk,
                t.category.all()[0].id,
                parent_namespace="TopicsSubMenu"
            )
            nodes.append(node)
        return nodes

menu_pool.register_menu(TopicsSubMenu)

就是这样!