Question

我有一个char数组，我需要转换为int，以便我可以对值进行数学运算。现在我能得到的最接近的是 - ＆gt;错误：请求'myData'中的成员'str'，它是非类型'char *'

代码：

char *getmyData()
{
        static char buff[BUFSIZ];
        FILE *fp = popen("php script.php 155", "r");
        std::fgets(buff,sizeof(buff),fp);
        return buff;
}

void mathFunc(){
        char *myData = getmyData();
        for (int i = 0; myData[i]; ++i) {
                int x;
                const char * cstr2 = myData.str().c_str();
                cstr2 >> x;
                for (int i = 0; i < size; ++i)
                        cout << x[i] + 10;
        }
}

错误：

 # g++ -g myDataunfuck.cpp -o myDataunfuck.o -std=gnu++11 -lcurl
myDataunfuck.cpp: In function 'void mathFunc()':
myDataunfuck.cpp:30:31: error: request for member 'str' in 'myData', which is of non-class type 'char*'
myDataunfuck.cpp:31:12: error: invalid operands of types 'const char*' and 'int' to binary 'operator>>'
myDataunfuck.cpp:32:23: error: 'size' was not declared in this scope
myDataunfuck.cpp:33:15: error: invalid types 'int[int]' for array subscript
myDataunfuck.cpp:44:1: error: a function-definition is not allowed here before '{' token
myDataunfuck.cpp:47:1: error: expected '}' at end of input

complete code

Answer 1

您可以执行以下操作： -

const char * cstr2 = myData;

Answer 2

您的myData变量是原始char*类型。它没有.可访问的任何方法。

c ++错误将* char转换为int

2 个答案: