Question

我试图理解如何重新组织一个程序，我之前将其编写为一系列状态转换：

我有一些商业逻辑：

type In = Long
type Count = Int 
type Out = Count
type S = Map[Int, Count]

val inputToIn: String => Option[In] 
  = s => try Some(s.toLong) catch { case _ : Throwable => None } 

def transition(in: In): S => (S, Out) 
  = s => { val n = s.getOrElse(in, 0); (s + (in -> n+1), n+1) }

val ZeroOut: Out = 0
val InitialState: S = Map.empty

有了这些我希望构建一个程序来传递一些初始状态（一个空的Map），从 stdin 读取输入，将其转换为In，运行状态转换和输出当前状态S和输出Out到标准输出。

以前，我会做这样的事情：

val runOnce = StateT[IO, S, Out](s => IO.readLn.map(inputToIn) flatMap { 
  case None     => IO((s, ZeroOut))
  case Some(in) => val (t, o) = transition(in)(s)
                   IO.putStrLn(t.toString) |+| IO.putStrLn(o.toString) >| IO((t, o))   
})

Stream.continually(runOnce).sequenceU.eval(InitialState)

但是，我真的很难看到如何将此方法（状态转换流）与 scalaz-stream 连接起来。我从这开始：

type Transition = S => (S, Out)
val NoTransition: Transition = s => (s, 0)

io.stdInLines.map(inputToIn).map(_.fold(NoTransition)(transition))

这是类型：Process[Task, Transition]。我真的不知道从哪里去。

我如何＆＃34;传递＆＃34;我的InitialState并运行程序，在每一步输出S中作为输入S到下一步？
如何在每一步获取S和Out的值并将其打印到 stdout （假设我可以将它们转换为字符串）？

在试图使用单一的理解时，我同样陷入困境：

for {
  i <- Process.eval(Task.now(InitialState))
  l <- io.stdInLines.map(inputToIn)
...

非常感谢任何帮助！

我现在有点进一步了。

type In_ = (S, Option[In])
type Out_ = (S, Out) 

val input: Process[Task, In_] 
  = for  {
      i <- Process.emit(InitialState) 
      o <- io.stdInLines.map(inputToIn)
   } yield (i, o)

val prog =
  input.pipe(process1.collect[In_, Out_]) {
    case (s, Some(in)) => transition(in)(s)
  }).to(io.stdOutLines.contramap[Out_](_.toString))

然后

prog.run.run

它不起作用：似乎状态不是通过流线程。相反，在每个阶段，初始状态都被传入。

Paul Chiusano建议使用process1.scan的方法。所以现在我这样做：

type In_  = In
type Out_ = (S, Out)

val InitialOut_ = (InitialState, ZeroOut)

val program =
  io.stdInLines.collect(Function.unlift(inputToIn)).pipe(
    process1.scan[In_, Out_](InitialOut_) {
      case ((s, _), in) => transition(in)(s)
    }).to(io.stdOutLines.contramap[Out_](_.shows))

这里有一个问题：在这个具体示例中，我的Out类型是 monoid ，因此我的初始状态可以使用其身份但通常情况可能并非如此。那我该怎么办？（我想我可以使用Option，但这似乎是不必要的。）

Answer 1

import io.FilePath

import scalaz.stream._
import Process._
import scalaz.concurrent.Task
import Task._
import scalaz.{Show, Reducer, Monoid}
import scalaz.std.list._
import scalaz.syntax.foldable._
import scalaz.syntax.bind._
import scalaz.stream._
import io._
import scalaz.stream.text._
import Processes._
import process1.lift
import control.Functions._

/**
 * A Fold[T] can be used to pass over a Process[Task, T].
 * 
 * It has:
 *
 *  - accumulation, with an initial state, of type S, a fold action and an action to perform with the last state
 *  
 *  - side-effects with a Sink[Task, (T, S)] to write to a file for example, using the current element in the Process
 *    and the current accumulated state
 *
 * This covers many of the needs of iterating over a Scalaz stream and is composable because there is a Monoid
 * instance for Folds
 * 
 */
trait Fold[T] {
  type S

  def prepare: Task[Unit]
  def sink: Sink[Task, (T, S)]
  def fold: (T, S) => S
  def init: S
  def last(s: S): Task[Unit]

  /** create a Process1 returning the state values */
  def foldState1: Process1[T, S] =
    Processes.foldState1(fold)(init)

  /** create a Process1 returning the folded elements and the state values */
  def zipWithState1: Process1[T, (T, S)] =
    Processes.zipWithState1(fold)(init)

}

/**
 * Fold functions and typeclasses
 */
object Fold {

  /**
   * Create a Fold from a Sink with no accumulation
   */
  def fromSink[T](aSink: Sink[Task, T]) =  new Fold[T] {
    type S = Unit
    lazy val sink: Sink[Task, (T, S)] = aSink.extend[S]

    def prepare = Task.now(())
    def fold = (t: T, u: Unit) => u
    def init = ()
    def last(u: Unit) = Task.now(u)
  }

  /**
   * Transform a simple sink where the written value doesn't depend on the
   * current state into a sink where the current state is passed all the time
   * (and actually ignored)
   * Create a Fold a State function
   */
  def fromState[T, S1](state: (T, S1) => S1)(initial: S1) = new Fold[T] {
    type S = S1
    lazy val sink: Sink[Task, (T, S)] = unitSink[T, S]

    def prepare = Task.now(())
    def fold = state
    def init = initial
    def last(s: S) = Task.now(())
  }

  /**
   * Create a Fold from a side-effecting function
   */
  def fromFunction[T](f: T => Task[Unit]): Fold[T] =
    fromSink(Process.constant(f))

  /**
   * Create a Fold from a Reducer
   */
  def fromReducer[T, S1](reducer: Reducer[T, S1]): Fold[T] = new Fold[T] {
    type S = S1
    lazy val sink: Sink[Task, (T, S)] = unitSink[T, S]

    def prepare = Task.now(())
    def fold = reducer.cons
    def init = reducer.monoid.zero
    def last(s: S) = Task.now(())
  }

  /**
   * Create a Fold from a Reducer and a last action
   */
  def fromReducerAndLast[T, S1](reducer: Reducer[T, S1], lastTask: S1 => Task[Unit]): Fold[T] = new Fold[T] {
    type S = S1
    lazy val sink: Sink[Task, (T, S)] = unitSink[T, S]

    def prepare = Task.now(())
    def fold = reducer.cons
    def init = reducer.monoid.zero
    def last(s: S) = lastTask(s)
  }

  /**
   * This Sink doesn't do anything
   * It can be used to build a Fold that does accumulation only
   */
  def unitSink[T, S]: Sink[Task, (T, S)] =
    channel((tu: (T, S)) => Task.now(()))

  /**
   * Unit Fold with no side-effect or accumulation
   */
  def unit[T] = fromSink(channel((t: T) => Task.now(())))

  /**
   * Unit fold function
   */
  def unitFoldFunction[T]: (T, Unit) => Unit = (t: T, u: Unit) => u

  /** create a fold sink to output lines to a file */
  def showToFilePath[T : Show, S](path: FilePath): Sink[Task, (T, S)] =
    io.fileChunkW(path.path).pipeIn(lift(Show[T].shows) |> utf8Encode).extend[S]

  implicit class FoldOps[T](val fold: Fold[T]) {
  }

  /**
   * Monoid for Folds, where effects are sequenced
   */
  implicit def foldMonoid[T]: Monoid[Fold[T]] = new Monoid[Fold[T]] {
    def append(f1: Fold[T], f2: =>Fold[T]): Fold[T] = f1 >> f2
    lazy val zero = Fold.unit[T]
  }

  /**
   * create a new Fold sequencing the effects of 2 Folds
   */
  implicit class sequenceFolds[T](val fold1: Fold[T]) {
    def >>(fold2: Fold[T]) = new Fold[T] {
      type S = (fold1.S, fold2.S)

      def prepare = fold1.prepare >> fold2.prepare

      def sink = fold1.sink.zipWith(fold2.sink) { (f1: ((T, fold1.S)) => Task[Unit], f2: ((T, fold2.S)) => Task[Unit]) =>
        (ts: (T, S)) => {
          val (t, (s1, s2)) = ts
          (f1((t, s1)) |@| f2((t, s2)))((_,_))
        }
      }

      def fold = (t : T, s12: (fold1.S, fold2.S)) => (fold1.fold(t, s12._1), fold2.fold(t, s12._2))
      def last(s12: (fold1.S, fold2.S)) = (fold1.last(s12._1) |@| fold2.last(s12._2))((_,_))
      def init = (fold1.init, fold2.init)
    }
  }

  /**
   * Run a fold an return the last value
   */
  def runFoldLast[T](process: Process[Task, T], fold: Fold[T]): Task[fold.S] =
    fold.prepare >>
    logged(process |> fold.zipWithState1).drainW(fold.sink).map(_._2).runLastOr(fold.init)

  /**
   * Run a Fold an let it perform a last action with the accumulated state
   */
  def runFold[T](process: Process[Task, T], fold: Fold[T]): Task[Unit] =
    runFoldLast(process, fold).flatMap(fold.last)

  /**
   * Run a list of Folds, sequenced with the Fold Monoid
   */
  def runFolds[T](process: Process[Task, T], folds: List[Fold[T]]): Task[Unit] =
    runFold(process, folds.suml)

}

如何使用scalaz-stream替换作为顺序状态转换流编写的程序？

1 个答案: