我有一百个左右的列,我想使用以下宏在SAS中重命名:
%macro rename1(oldvarlist, newvarlist);
%let k=1;
%let old = %scan(&oldvarlist, &k);
%let new = %scan(&newvarlist, &k);
%do %while(("&old" NE "") & ("&new" NE ""));
rename &old = &new;
%let k = %eval(&k + 1);
%let old = %scan(&oldvarlist, &k);
%let new = %scan(&newvarlist, &k);
%end;
%mend;
这些列目前被命名为C5,C7,C9,...,C205,我想将它们重命名为AR_0,AR_1,...,AR100。
使用上面的宏,如何将这些新名称放在以下代码的逗号之后而不编写每个代码?
%rename1(C5--C205, # new names here #);
答案 0 :(得分:1)
这是一个较长的解决方案,但它相当动态,你很容易看出事情是如何运作的。我假设您将在proc数据集中使用重命名语句。否则你可能只是懒惰并使用数组替换然后删除旧变量,虽然这不是有效的。
proc sql;
create table oldvar as
select name, varnum
from sashelp.vcolumn
where upcase(libname)='SASHELP'
and upcase(memname)='CLASS'
order by varnum;
quit;
data rename;
set oldvar;
new_var=catx("_", "AR",varnum);
run;
proc sql noprint;
select catx("=", name, new_var) into :rename_list
separated by " "
from rename;
quit;
%put rename &rename_list;
proc datasets library=work;
modify my_dataset;
rename &rename_list;
run;quit;
答案 1 :(得分:1)
首先找到旧列并将它们重命名为AR_#并创建可以使用的宏变量varlist:
proc sql noprint;
create table newvar as
select name
from sashelp.vcolumn
where libname="SASHELP" and memname="CLASS"
order by name;
quit;
data newvar;
set newvar;
name=compress("AR_"!!put(_n_,4.));
run;
proc sql noprint;
select name into :varlist separated by " "
from newvar;
quit;
答案 2 :(得分:0)
可能这样的事情可以胜任
%macro rename2(oldvarlist, newPrefix);
%let k=1;
%let old = %scan(&oldvarlist, &k);
%do %while(("&old" NE ""));
rename &old = &newPrefix.&k.;
%let k = %eval(&k + 1);
%let old = %scan(&oldvarlist, &k);
%end;
%mend;