Question

我正在尝试运行以下Xquery：

for $a1 in doc("TSS_Data.xml")/root/auditions/audition, $a2 in doc("TSS_Data.xml")/root/auditions/audition
where ($a1/@ID != $a2/@ID and $a1/@contestantId != $a2/@contestantId and $a1/@artworkId = $a2/@artworkId and 
$a1/@showId = $a2/@showId)
    for $s1 in doc("TSS_Data.xml")/root/scores/score[@auditionId = $a1/@ID], 
    $s2 in doc("TSS_Data.xml")/root/scores/score[@auditionId = $a2/@ID]
        return data (doc("TSS_Data.xml")/root/contestants/contestant[@ID = $a1/@contestantId]/@name)

但是我收到了一个错误，意外的令牌＆＃34;因为＆＃34;在第4行。这是错误的语法吗？如何写一个＆＃34; for＆＃34;循环在＆＃34;其中＆＃34;条款？

Answer 1

for始终需要return语句，就像在内循环中所做的那样。因此，它应该是

for $a1 in doc("TSS_Data.xml")/root/auditions/audition, $a2 in doc("TSS_Data.xml")/root/auditions/audition
where ($a1/@ID != $a2/@ID and $a1/@contestantId != $a2/@contestantId and $a1/@artworkId = $a2/@artworkId and $a1/@showId = $a2/@showId)
return
    for $s1 in doc("TSS_Data.xml")/root/scores/score[@auditionId = $a1/@ID], 
    $s2 in doc("TSS_Data.xml")/root/scores/score[@auditionId = $a2/@ID]
        return data (doc("TSS_Data.xml")/root/contestants/contestant[@ID = $a1/@contestantId]/@name)

想在Xquery的“where”子句中包含“for”语句

1 个答案: