Java代码:
PhoneListAdapter adapter = new PhoneListAdapter(this,brands,models,price);
lv=(ListView)findViewById(R.Id.listView1);
lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> Parent,View view, int position,
long id) {
// TODO Auto-generated method stub
Toast.makeText(getApplicationContext(),"listview clicked", Toast.LENGTH_LONG).show();
}
});
XML:
<RelativeLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_weight="1" >
<ListView
android:id="@+id/listView1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_alignParentLeft="true"
android:layout_alignParentTop="true"
android:layout_marginLeft="80dp"
android:clickable="true">
</ListView>
</RelativeLayout></LinearLayout>
我已经做了所有事情,如果我用硬编码的字符串推出一个吐司,它会出现,但listview的任何方法都返回null。我错过了什么???
答案 0 :(得分:0)
嘿,如果品牌,型号,价格是数组列表,请使用下面的内容。
lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> Parent,View view, int position,
long id) {
// TODO Auto-generated method stub
Assign the String or integer what ever you want. = brands .get(position).get if you have getter and setter methods.
Toast.makeText(getApplicationContext(),"listview clicked", Toast.LENGTH_LONG).show();
}
});
答案 1 :(得分:0)
@Piyush Gupta
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/RelativeLayout1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="#33ffffff" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignBaseline="@+id/imageView1"
android:layout_alignParentTop="true"
android:layout_marginTop="10dip"
android:layout_toRightOf="@+id/imageView1"
android:text="Textview"
android:textAppearance="?android:attr/textAppearanceLarge"
android:textColor="#000000" />