如何修复名称分类器? NoSuchElementFound错误......?

时间:2014-11-17 04:26:14

标签: java sorting debugging

我编写了名称排序程序,用于对名称列表(duh)进行排序,并给出我姓名的索引值。由于某种原因它编译得很好,但是说'maleNames [i] = nameScan.nextLine();“并返回此消息:

java.util.NoSuchElementException: No line found
    at java.util.Scanner.nextLine(Scanner.java:1540)
    at NameSorter.main(NameSorter.java:14)

任何想法或修复?提前谢谢!

import java.io.*;
import java.util.Scanner;
public class NameSorter
{
    public static void main(String [] args) throws FileNotFoundException
    {
        String [] maleNames = new String[1220];
        PrintStream ps = new PrintStream("sorted_male_names.txt");

        Scanner nameScan = new Scanner(new File("common_male_names.txt"));

        for (int i = 0; i < maleNames.length; i++)
        {
            maleNames[i] = nameScan.nextLine();
        }

        bubbleSort(maleNames);

        for (int i = 0; i < maleNames.length; i++)
        {
            System.out.println(maleNames[i]);
        }

        for (int i = 0; i < maleNames.length; i++)
        {
            String currentName = maleNames[i];
            ps.println(currentName);
        }

        System.out.println(linearSearch(maleNames, "zander"));
    }

    public static boolean isSorted(String[] arr)
    {
        for (int i = 0; i < arr.length -1; i++)
        {
            if (arr[i].compareTo(arr[i+1]) > 0)
                return false;
            }
        return true;
    }

    public static void swapElements(String[] arr, int index1, int index2)
    {
        String tempValue = arr[index1];
        arr[index1] = arr[index2];
        arr[index2] = tempValue;
    }

    public static void bubbleSort(String[] arr)
    {
        while(isSorted(arr) == false) // while(!isSorted(arr)) 
        {
        for (int i = 0; i < arr.length - 1; i++)
        {
            if (arr[i].compareTo(arr[i+1]) > 0)
            swapElements(arr, i, i+1);
        }
        }
    }

    public static int linearSearch(String[] arr, String name)
    {
        for (int i = 0; i > arr.length; i++)
        {
            if (arr[i].equals(name))
            return i;
        }
        return -1;
    }

    public static void printArray(int[] arr)
    {
        for (int i = 0; i < arr.length; i++)
        {
            System.out.print(arr[i] + " ");
        }
    }
}

1 个答案:

答案 0 :(得分:2)

你的for循环

for (int i = 0; i < maleNames.length; i++) {
        maleNames[i] = nameScan.nextLine();
}

假设文件中有maleNames.length个元素(在这种情况下为1220),如果少于NoSuchElementException

更好的方法是使用扫描仪的hasNextLine()方法和List<String>

List<String> maleNames = new ArrayList<>();

while(nameScan.hasNextLine()) { 
    maleNames.add(nameScan.nextLine());
}

这将允许任何长度的名称文件,只要其格式正确,并避免您的异常。