Question

我需要一个可以执行以下操作的python函数：

给出输入＆＃39; t＆＃39;并且＆＃39; tattle＆＃39;它应该返回如下列表： [＆＃39;闲话＆＃39;＆＃39;闲话＆＃39;＆＃39;闲话＆＃39;] 或者使用＆＃39; z＆＃39;和＆＃39; zzzzz＆＃39;： [＆＃39; ZZZZZ＆＃39;＆＃39; ZZZZZ＆＃39;＆＃39; ZZZZZ＆＃39;＆＃39; ZZZZZ＆＃39;＆＃39; ZZZZZ＆＃39;]

我对以下内容进行了编码，但它不适用于第二个示例，因为当前函数会检查basestr是否与结果列表R中已有的匹配，并且由于具有多个basetr＆的单词而可以获取误报＃39;已经在这个词中了。有人有什么建议吗？

def all_variants(wrapletter,word):
    L,R,WLU,basestr=list(word),[],wrapletter.upper(),''
    if L.count(wrapletter)==1:
        for char in L:
            if wrapletter==char:
                basestr=basestr+WLU
            else:
                basestr=basestr+char
        R.append(basestr)
        return(R)
    else:
        for i in range(L.count(wrapletter)):
            basestr=''
            if i==0 and L[0]==wrapletter:
                basestr=WLU
                for char in range(1,len(L)):
                    basestr=basestr+L[char]
                R.append(basestr)
            else:
                for char in L:
                    if wrapletter==char:
                        if WLU in basestr:
                            basestr=basestr+char
                        elif basestr in str(R):
                            basestr=basestr+char
                        else:
                            basestr=basestr+WLU
                    else:
                        basestr=basestr+char
            R.append(basestr)
        R.remove(R[0])
        return(R)

Answer 1

它不优雅，但也许这就是你需要的东西？

target = "daaddaad"

def capitalize(target_letter, word):
    return [word[:i] + word[i].upper() + word[i + 1:]
            for i in xrange(len(word)) if word[i] == target_letter]

print capitalize("d", target)

输出：

['Daaddaad', 'daaDdaad', 'daadDaad', 'daaddaaD']

Answer 2

def all_variants(wrapletter, word):
    list = []
    for i in range(len(word)):
        if(word[i]==wrapletter):
            start = word[0:i].lower()
            str = word[i].upper()
            end = word[i+1::].lower()
            list.append(start+str+end)
    return list

运行此功能时返回：

>>>all_variants("t", "tattle")
['Tattle', 'taTtle', 'tatTle']

>>>all_variants("z", "zzzzz")
['Zzzzz', 'zZzzz', 'zzZzz', 'zzzZz', 'zzzzZ']

Answer 3

inp = 't'
word = 'tattle'
inds = (i for i,ele in enumerate(word) if ele == inp)

print([word[:i]+word[i].upper()+word[i+1:] for i in inds])
['Tattle', 'taTtle', 'tatTle']

Answer 4

试试这个。我遍历每个字母，将其移至大写，并将其与原始字符串的其他部分夹在一起。

def all_variants(wrapletter, word):
    variants = []
    for i, letter in enumerate(word):
        if letter == wrapletter:
            variants.append(word[:i] + letter.upper() + word[i+1:])
    return variants

print all_variants('z', 'zzzzz')
print all_variants('t', 'tattle')

寻找所有变化的词与移位大写字母

4 个答案: