将Java对象转换为XML字符串

时间：2014-11-16 16:38:02

标签： java xml jaxb

是的，我知道有很多关于这个话题的问题。但我仍然无法找到解决问题的方法。我有一个属性注释的Java对象。例如Customer，like in this example。我想要一个String表示它。谷歌建议将JAXB用于此类目的。但是在所有示例中，创建的XML文件都打印到文件或控制台，如下所示：

File file = new File("C:\\file.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

jaxbMarshaller.marshal(customer, file);
jaxbMarshaller.marshal(customer, System.out);

但我必须使用此对象并以XML格式通过网络发送。所以我想得到一个代表XML的String。

String xmlString = ...
sendOverNetwork(xmlString);

我该怎么做？

13 个答案:

答案 0 :(得分：90)

您可以使用Marshaler的编组方法，以Writer为参数：

  

marshal(Object,Writer)

并传递一个可以构建String对象的实现

  

直接已知子类：   BufferedWriter，CharArrayWriter，FilterWriter，OutputStreamWriter，PipedWriter，PrintWriter，StringWriter

调用其toString方法获取实际的字符串值。

这样做：

StringWriter sw = new StringWriter();
jaxbMarshaller.marshal(customer, sw);
String xmlString = sw.toString();

答案 1 :(得分：30)

如A4L所述，您可以使用StringWriter。这里提供示例代码：

private static String jaxbObjectToXML(Customer customer) {
    String xmlString = "";
    try {
        JAXBContext context = JAXBContext.newInstance(Customer.class);
        Marshaller m = context.createMarshaller();

        m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); // To format XML

        StringWriter sw = new StringWriter();
        m.marshal(customer, sw);
        xmlString = sw.toString();

    } catch (JAXBException e) {
        e.printStackTrace();
    }

    return xmlString;
}

答案 2 :(得分：25)

方便的选择是使用javax.xml.bind.JAXB：

StringWriter sw = new StringWriter();
JAXB.marshal(customer, sw);
String xmlString = sw.toString();

反向过程（unmarshal）将是：

Customer customer = JAXB.unmarshal(new StringReader(xmlString), Customer.class);

无需处理此方法中的已检查异常。

答案 3 :(得分：6)

您可以将其编组为StringWriter并抓住其字符串。来自toString()。

答案 4 :(得分：2)

将对象转换为Java中的XML

Customer.java 

package com;

import java.util.ArrayList;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

/**
*
* @author ABsiddik
*/

@XmlRootElement
public class Customer {

int id;
String name;
int age;

String address;
ArrayList<String> mobileNo;


 public int getId() {
    return id;
}

@XmlAttribute
public void setId(int id) {
    this.id = id;
}

public String getName() {
    return name;
}

@XmlElement
public void setName(String name) {
    this.name = name;
}

public int getAge() {
    return age;
}

@XmlElement
public void setAge(int age) {
    this.age = age;
}

public String getAddress() {
    return address;
}

@XmlElement
public void setAddress(String address) {
    this.address = address;
}

public ArrayList<String> getMobileNo() {
    return mobileNo;
}

@XmlElement
public void setMobileNo(ArrayList<String> mobileNo) {
    this.mobileNo = mobileNo;
}


}

ConvertObjToXML.java 

package com;

import java.io.File;
import java.io.StringWriter;
import java.util.ArrayList;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

/**
*
* @author ABsiddik
*/
public class ConvertObjToXML {

public static void main(String args[]) throws Exception
{
    ArrayList<String> numberList = new ArrayList<>();
    numberList.add("01942652579");
    numberList.add("01762752801");
    numberList.add("8800545");

    Customer c = new Customer();

    c.setId(23);
    c.setName("Abu Bakar Siddik");
    c.setAge(45);
    c.setAddress("Dhaka, Bangladesh");
    c.setMobileNo(numberList);

    File file = new File("C:\\Users\\NETIZEN-ONE\\Desktop \\customer.xml");
    JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    jaxbMarshaller.marshal(c, file);// this line create customer.xml file in specified path.

    StringWriter sw = new StringWriter();
    jaxbMarshaller.marshal(c, sw);
    String xmlString = sw.toString();

    System.out.println(xmlString);
}

}

试试这个例子..

答案 5 :(得分：1)

测试并使用Java代码将Java对象转换为XML：

<强> Customer.java 

import java.util.ArrayList;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;


@XmlRootElement
public class Customer {

    String name;
    int age;
    int id;
    String desc;
    ArrayList<String> list;

    public ArrayList<String> getList()
    {
        return list;
    }

    @XmlElement
    public void setList(ArrayList<String> list)
    {
        this.list = list;
    }

    public String getDesc()
    {
        return desc;
    }

    @XmlElement
    public void setDesc(String desc)
    {
        this.desc = desc;
    }

    public String getName() {
        return name;
    }

    @XmlElement
    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    @XmlElement
    public void setAge(int age) {
        this.age = age;
    }

    public int getId() {
        return id;
    }

    @XmlAttribute
    public void setId(int id) {
        this.id = id;
    }
}

<强> createXML.java 

import java.io.StringWriter;
import java.util.ArrayList;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;


public class createXML {

    public static void main(String args[]) throws Exception
    {
        ArrayList<String> list = new ArrayList<String>();
        list.add("1");
        list.add("2");
        list.add("3");
        list.add("4");
        Customer c = new Customer();
        c.setAge(45);
        c.setDesc("some desc ");
        c.setId(23);
        c.setList(list);
        c.setName("name");
        JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        StringWriter sw = new StringWriter();
        jaxbMarshaller.marshal(c, sw);
        String xmlString = sw.toString();
        System.out.println(xmlString);
    }

}

答案 6 :(得分：1)

使用ByteArrayOutputStream 

public static String printObjectToXML(final Object object) throws TransformerFactoryConfigurationError,
        TransformerConfigurationException, SOAPException, TransformerException
{
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    XMLEncoder xmlEncoder = new XMLEncoder(baos);
    xmlEncoder.writeObject(object);
    xmlEncoder.close();

    String xml = baos.toString();
    System.out.println(xml);

    return xml.toString();
}

答案 7 :(得分：0)

一些通用代码来创建XML Stirng

object->是将其转换为XML的Java类
name->就像名称空间一样，用于区分 

public static String convertObjectToXML(Object object,String name) {
          try {
              StringWriter stringWriter = new StringWriter();
              JAXBContext jaxbContext = JAXBContext.newInstance(object.getClass());
              Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
              jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
              QName qName = new QName(object.getClass().toString(), name);
              Object root = new JAXBElement<Object>(qName,java.lang.Object.class, object);
              jaxbMarshaller.marshal(root, stringWriter);
              String result = stringWriter.toString();
              System.out.println(result);
              return result;
        }catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }

答案 8 :(得分：0)

我采用了JAXB.marshal实现，并添加了jaxb.fragment = true来删除XML序言。即使没有XmlRootElement批注，此方法也可以处理对象。这也会引发未经检查的DataBindingException。

public static String toXmlString(Object o) {
    try {
        Class<?> clazz = o.getClass();
        JAXBContext context = JAXBContext.newInstance(clazz);
        Marshaller marshaller = context.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true); // remove xml prolog
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); // formatted output

        final QName name = new QName(Introspector.decapitalize(clazz.getSimpleName()));
        JAXBElement jaxbElement = new JAXBElement(name, clazz, o);

        StringWriter sw = new StringWriter();
        marshaller.marshal(jaxbElement, sw);
        return sw.toString();

    } catch (JAXBException e) {
        throw new DataBindingException(e);
    }
}

如果编译器警告困扰您，那么这是模板化的两个参数版本。

public static <T> String toXmlString(T o, Class<T> clazz) {
    try {
        JAXBContext context = JAXBContext.newInstance(clazz);
        Marshaller marshaller = context.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true); // remove xml prolog
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); // formatted output

        QName name = new QName(Introspector.decapitalize(clazz.getSimpleName()));
        JAXBElement jaxbElement = new JAXBElement<>(name, clazz, o);

        StringWriter sw = new StringWriter();
        marshaller.marshal(jaxbElement, sw);
        return sw.toString();

    } catch (JAXBException e) {
        throw new DataBindingException(e);
    }
}

答案 9 :(得分：0)

这里是用于封送和拆封对象的util类。就我而言，这是一个嵌套类，因此我将其设置为静态JAXBUtils。 

import javax.xml.bind.JAXB;
import java.io.StringReader;
import java.io.StringWriter;

public class JAXBUtils
{
    /**
     * Unmarshal an XML string
     * @param xml     The XML string
     * @param type    The JAXB class type.
     * @return The unmarshalled object.
     */
    public <T> T unmarshal(String xml, Class<T> type)
    {
        StringReader reader = new StringReader(xml);
        return javax.xml.bind.JAXB.unmarshal(reader, type);
    }

    /**
     * Marshal an Object to XML.
     * @param object    The object to marshal.
     * @return The XML string representation of the object.
     */
    public String marshal(Object object)
    {
        StringWriter stringWriter = new StringWriter();
        JAXB.marshal(object, stringWriter);
        return stringWriter.toString();
    }
}

答案 10 :(得分：0)

Underscore-java 可以在构建器的帮助下构造 XML 字符串。

    class Customer {
        String name;
        int age;
        int id;
    }
    Customer customer = new Customer();
    customer.name = "John";
    customer.age = 30;
    customer.id = 12345;

    String xml = U.objectBuilder().add("customer", U.objectBuilder()
        .add("name", customer.name)
        .add("age", customer.age)
        .add("id", customer.id)).toXml();

    // <?xml version="1.0" encoding="UTF-8"?>
    //    <customer>
    //      <name>John</name>
    //      <age number="true">30</age>
    //      <id number="true">12345</id>
    //    </customer>

答案 11 :(得分：-1)

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;

private String generateXml(Object obj, Class objClass) throws JAXBException {
        JAXBContext jaxbContext = JAXBContext.newInstance(objClass);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        StringWriter sw = new StringWriter();
        jaxbMarshaller.marshal(obj, sw);
        return sw.toString();
    }

答案 12 :(得分：-1)

使用此函数将Object转换为xml字符串 （应该称为convertToXml（sourceObject，Object.class）;） - ＆gt; 

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.namespace.QName;

public static <T> String convertToXml(T source, Class<T> clazz) throws JAXBException {
    String result;
    StringWriter sw = new StringWriter();
    JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
    QName qName = new QName(StringUtils.uncapitalize(clazz.getSimpleName()));
    JAXBElement<T> root = new JAXBElement<T>(qName, clazz, source);
    jaxbMarshaller.marshal(root, sw);
    result = sw.toString();
    return result;
}

使用此函数将xml字符串转换为Object back - ＆gt; （应该被称为createObjectFromXmlString(xmlString, Object.class)）

public static <T> T createObjectFromXmlString(String xml, Class<T> clazz) throws JAXBException, IOException{

    T value = null;
    StringReader reader = new StringReader(xml); 
    JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
    Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
    JAXBElement<T> rootElement=jaxbUnmarshaller.unmarshal(new StreamSource(reader),clazz);
    value = rootElement.getValue();
    return value;
}
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